Perimeter is proportional to the linear dimensions, so it increases by 3x .
Area is proportional to (linear dimensions)2, so it increases by 9x .
3 and 9 respectively.
Area is proportional to the square of the linear dimensions.If diameter is tripled, area increases by a factor of (3)2 = 9 .
divide the perimeter by 27 the multiply it by 3 and then u get the answer
There need not be any. There is no scale factor between a pentagon with a perimeter of 50 cm and a triangle with a perimeter of 75 cm. The shapes are totally different!The scale factor is 2 : 3.
If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.
the answer to this question is 1:4 10: ? =10x4/1 =40
three times
Area is proportional to the square of the linear dimensions.If diameter is tripled, area increases by a factor of (3)2 = 9 .
The perimeter correspondingly increases by a factor of 4.
It is a strict linear relationship. Double the size, double the perimeter. The area, however, increases by the square of the scale factor.
If the radius is tripled then the Area will be greater by a factor of 9. And the circumference will be greater by a factor of 3.
divide the perimeter by 27 the multiply it by 3 and then u get the answer
The absolute value of the perimeter doesn't change, only the unit value which increases by a factor of 3.
If linear dimensions are increased by a certain factor, the volume will increase by that same factor, raised to the third power - so, in this case, 3 to the power 3.
Scale factor and perimeter are related because if the scale factor is 2, then the perimeter will be doubled. So whatever the scale factor is, that is how many times the perimeter will be enlarged.
Theorem: If two similar triangles have a scalar factor a : b, then the ratio of their perimeters is a : bBy the theorem, the ratio of the perimeters of the similar triangles is 2 : 3.For rectangles, perimeter is 2*(L1 + W1). If the second rectangle's sides are scaled by a factor S, then its perimeter is 2*(S*L1 + S*W1) = S*2*(L1 + W1), or the perimeter of the first, multiplied by the same factor S.In general, if an N-sided polygon has sides {x1, x2, x3....,xN}, then its perimeter is x1 + x2 + x3 + ... + xN. If the second similar polygon (with each side (labeled y, with corresponding subscripts) scaled by S, so that y1 = S*x1, etc. The perimeter is y1 + y2 + ... + yN = S*x1 + S*x2 + ... + S*xN = S*(x1 + x2 + ... + xN ),which is the factor S, times the perimeter of the first polygon.
The perimeter will scale by the same factor.
New perimeter = old perimeter*scale factor New area = Old area*scale factor2