The area changes by the square of the same factor.
The perimeter, being a linear measure, also changes by a factor of 3.
The surface area is reduced by a factor 4, the volume by a factor 8.
If the dimensions of a cone are doubled, both its height and radius increase by a factor of two. As a result, the volume of the cone, which is calculated using the formula ( V = \frac{1}{3} \pi r^2 h ), would increase by a factor of eight, since volume is proportional to the cube of the dimensions. The surface area would also increase, but by a smaller factor of four, as surface area scales with the square of the dimensions. Thus, the cone would become significantly larger in both volume and surface area.
If it is a 2-dimensional figure then it is proportional.
False. If the dimensions of a rectangular prism are quadrupled, the surface area will increase by a factor of 16, not 8. This is because surface area is proportional to the square of the dimensions, so if each dimension is multiplied by 4, the surface area increases by (4^2 = 16).
Volume = area circular end × height = πR²H units³ Surface area = 2 × area of circular end + area of curved side = 2πR² + 2πRH units² = 2πR(R + H) units² If lengths are changed by a scale factor of n, areas are changed by a scale factor of n² and volumes are changed by a scale factor of n³. If the dimensions are tripled, the new volume is 3³πR²H units³ = 27πR²H units³ The new surface area is 3²×2πR(R + H) units² = 18πR(R + H) units²
The perimeter, being a linear measure, also changes by a factor of 3.
The surface area is reduced by a factor 4, the volume by a factor 8.
If linear dimensions are increased by a certain factor, the volume will increase by that same factor, raised to the third power - so, in this case, 3 to the power 3.
If the dimensions of a cone are doubled, both its height and radius increase by a factor of two. As a result, the volume of the cone, which is calculated using the formula ( V = \frac{1}{3} \pi r^2 h ), would increase by a factor of eight, since volume is proportional to the cube of the dimensions. The surface area would also increase, but by a smaller factor of four, as surface area scales with the square of the dimensions. Thus, the cone would become significantly larger in both volume and surface area.
The surface area increase by a factor of 49.
If it is a 2-dimensional figure then it is proportional.
Nothing. The cylinder's surface area does not have a GCF.
False. If the dimensions of a rectangular prism are quadrupled, the surface area will increase by a factor of 16, not 8. This is because surface area is proportional to the square of the dimensions, so if each dimension is multiplied by 4, the surface area increases by (4^2 = 16).
if all 3 dimensions increase b factor of 7 then volume changes by 7 cubed or a factor of 343
The absolute value of the perimeter doesn't change, only the unit value which increases by a factor of 3.
When the dimensions of a cube are doubled, each side length increases from ( s ) to ( 2s ). The surface area of a cube is calculated as ( 6s^2 ); therefore, the new surface area becomes ( 6(2s)^2 = 6 \times 4s^2 = 24s^2 ). This shows that the new surface area is four times greater than the original surface area of ( 6s^2 ). Hence, when the dimensions are doubled, the surface area indeed increases by a factor of four.