10x and 6y are terms of an algebraic expression
Subtracting gives: 10x = 80 so x = 8 and y = 5
X=7 y=5
If 10x + 6y = 24, y = (24 - 10x)/6 = 4 - (5/3)x. The slope of a line with an equation written in this format is the coefficient of x, therefore -(5/3).
x(y - 10) + 6y
2y
An equals sign seems to be missing. If it is -10x=6y-30 then the slope is -5/3. If it is -10x+6y-30=0 then it is 5/3.
Subtracting gives: 10x = 80 so x = 8 and y = 5
Two straight lines that intersect.
X=7 y=5
If 10x + 6y = 24, y = (24 - 10x)/6 = 4 - (5/3)x. The slope of a line with an equation written in this format is the coefficient of x, therefore -(5/3).
10x and 6y are terms of an algebraic expression
x(y - 10) + 6y
2y
4x+6y=62 -6x+6y=-18 what is the ordered pair
That should say 6x+6y=-24
xy - 10x + 6y - 60 = x(y - 10) + 6(y - 10) = (y - 10)(x + 6)
The equation of the circle with center (h, k) and radius r is of the form(x - h)2 + (y - k)2 = r2x2 + y2 - 10x + 6y = 47 (complete the square)[x2 - 10x + (10/2)2] + [y2 + 6y +(6/2)2] = 47 + (10/2)2 +(6/2)2(x2 - 10x + 52) + (y2 + 6y + 32) = 47 + 52 + 32(x - 5)2 + (y + 3)2 = 81(x - 5)2 + (y + 3)2 = 92So that the center of the circle is (5, -3) and the radius is 9.