The electric flux depends on charge, when the charge is zero the flux is zero. The electric field depends also on the charge. Thus when the electric flux is zero , the electric field is also zero for the same reason, zero charge.
Phi= integral E.dA= integral zcDdA = zcQ
Phi is zcQ and depends on charge Q, as does E.
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No.there can be electric field on the Gaussian surface even if the charge enclosed by it is zero.However ,net flux will be zero through the surface.
When the two charges are of same polarity then field becomes zero on its axial line but in between the two charges. If they are of opposite polarity then at points outside not in between there will be one point where the net electric field becomes zero. That point will be nearer to the weaker charge ie closer to the weaker and far from the stronger one.
Using the Gauss' Law of Magnetism We know total flux will be zero flux(top)+flux(bottom)+flux(curved side)=0 ------- (a) flux(bottom)= -25e-3 (GIVEN) (-ve shows inward direction) flux(top)=B*A=(1.6e-3)*[3.14*(0.12)^2]=2.304e-5 Put the values in eq (a) you'll get flux(curved side)= +24.97e-3 (+ve shows direction is outward)
Compound
zero