There is a one out of four chance of having both dice even numbers.
It is 1/4.
The answer depends on how many dice you roll and how often. If you roll four dice once, the probability of getting a double AND two odd numbers is 264/1296 = 11/54
Rolling the dice once will result in any one of the six numbers having the same probability of being up. The probability of getting a '5' = 1/6, the same as getting a '1.' ============================
1 in 6. As there are 6 different numbers. 1/6 as a fraction
The probability of rolling two even numbers on two standard dice is 0.52, or 0.25.
There is a one out of four chance of having both dice even numbers.
It is 1/4.
The answer depends on how many dice you roll and how often. If you roll four dice once, the probability of getting a double AND two odd numbers is 264/1296 = 11/54
Rolling the dice once will result in any one of the six numbers having the same probability of being up. The probability of getting a '5' = 1/6, the same as getting a '1.' ============================
1 in 6. As there are 6 different numbers. 1/6 as a fraction
Rolling a dice and getting an even number is an outcome. It is the result of rolling a dice.
6
I'm assuming your question is the same as this: "If 2 dice are rolled, what is the probability of not getting 1 on either die?" To answer this question, we need to look at what IS possible. If I'm 2 rolling normal, fair dice, then I have equal probability of getting each of the numbers 1-6 on either die. If I'm trying to NOT get 1, then I want to get any of the numbers 2-6 on both dice. This gives me 10 desired outcomes (5 numbers * 2 dice) out of 12 possible outcomes (6 numbers * 2 dice), so the probability is 10/12, which simplifies to 5/6.
The odds are 1:3. The probability is 1/4 or 25%.
The answer depends on what is being rolled, how many times and also on what variable is being recoded.
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.