No. All of the permutations are equally likely, but the distinguishable combinations, and the permutations of the same sum are not. Take two dice, for instance. There are 36 permutations. The sums 2 and 12 each have only one permutation, so their probabilities are 1 in 36, each. The sum 7, however, has 6 permutations, 1-6, 2-5, 3-4, 4-3, 5-2, and 6-1, so the probability of a sum of 6 is 6 in 36, or 1 in 6.
There are 9 odd sums that you can get from rolling two dice.
When rolling 2 dice there are 36 combinations that can occur. Sums will range from 2 to 12; sums divided by 4 are 4, 8, and 12 You can get this by dice combinations of 1 3 3 1 2 2 4 4 2 6 6 2 3 5 5 3 6 6 That is 9 ways. so odds are 9/36 = 1 in 4
The sums divisible by 3 are 3, 6, 9 and 12. These can be obtained in 2, 5, 4 and 1 ways respectively, giving 2 + 5 + 4 + 1 = 12 ways of success. There are 36 possible ways two dice can fall → probability = ways_of_success/possible_ways = 12/36 = 1/3.
On two fair 6-sided dice: 5 out of 36 = 13.89%. Consider the two dice unique. Maybe one is black with white spots, and the other is white with black spots. There are 36 possible outcomes. You can make a table of the sums, and see that five of the outcomes have a sum of 6. Here they are:1+5, 2+4, 3+3, 4+2, 5+1
There are 36 possible outcomes when throwing 2 dices : 6 for the first dice (1,2,3,...6) and 6 for the second dice Let say that in the sums below the first number is the result of the first dice and the second number is for the result of the second dice: 2 = 1 + 1: 1 possibility 4 = 2 + 2 = 1 + 3 = 3 + 1: 3 possibilities 6 = 1 + 5 = 5 + 1 = 2 + 4 = 4 + 2 = 3 +3: 5 possibilities 1 + 3 + 5 = 9 possibilities to get 2 or 4 or 6 So the probability to get a sum of 2 or 4 or 6 is 9/36=1/4 And the probabilty of NOT rolling a sum of 2 or 4 or 6 is 1-1/4=3/4
There are 9 odd sums that you can get from rolling two dice.
You can get 2, 4, 6, 8, 10, and 12, six even sums all together.
The most probable result of rolling two dice is a sum of seven. The probability of rolling a seven is 1 in 6 or about 0.167.All of the other possible sums have decreasing probability, all the way down to 1 in 36 or about 0.0278 for a sum of two or a sum of 12.
When rolling 2 dice there are 36 combinations that can occur. Sums will range from 2 to 12; sums divided by 4 are 4, 8, and 12 You can get this by dice combinations of 1 3 3 1 2 2 4 4 2 6 6 2 3 5 5 3 6 6 That is 9 ways. so odds are 9/36 = 1 in 4
5
There are 216 permutations of three dice. Of these, 206 have a sum that is less than 16, specifically, the permutations 466, 556, 565, 566, 646, 655, 656, 664, 665, and 666 have sums that are 16 or greater - all other permutations have sums that are less than 16. The probability, then, of rolling a sum less than 16 on three dice is 206 in 216, or about 0.9537.
The sums divisible by 3 are 3, 6, 9 and 12. These can be obtained in 2, 5, 4 and 1 ways respectively, giving 2 + 5 + 4 + 1 = 12 ways of success. There are 36 possible ways two dice can fall → probability = ways_of_success/possible_ways = 12/36 = 1/3.
216/3 = 72
12, because you can only get it one way: 6+6=12 And 2, because get it one way: 1+1=2.
On two fair 6-sided dice: 5 out of 36 = 13.89%. Consider the two dice unique. Maybe one is black with white spots, and the other is white with black spots. There are 36 possible outcomes. You can make a table of the sums, and see that five of the outcomes have a sum of 6. Here they are:1+5, 2+4, 3+3, 4+2, 5+1
There are 36 possible outcomes when throwing 2 dices : 6 for the first dice (1,2,3,...6) and 6 for the second dice Let say that in the sums below the first number is the result of the first dice and the second number is for the result of the second dice: 2 = 1 + 1: 1 possibility 4 = 2 + 2 = 1 + 3 = 3 + 1: 3 possibilities 6 = 1 + 5 = 5 + 1 = 2 + 4 = 4 + 2 = 3 +3: 5 possibilities 1 + 3 + 5 = 9 possibilities to get 2 or 4 or 6 So the probability to get a sum of 2 or 4 or 6 is 9/36=1/4 And the probabilty of NOT rolling a sum of 2 or 4 or 6 is 1-1/4=3/4
Any number between 2 and 12.1+16+6