No. All of the permutations are equally likely, but the distinguishable combinations, and the permutations of the same sum are not. Take two dice, for instance. There are 36 permutations. The sums 2 and 12 each have only one permutation, so their probabilities are 1 in 36, each. The sum 7, however, has 6 permutations, 1-6, 2-5, 3-4, 4-3, 5-2, and 6-1, so the probability of a sum of 6 is 6 in 36, or 1 in 6.
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There are 9 odd sums that you can get from rolling two dice.
When rolling 2 dice there are 36 combinations that can occur. Sums will range from 2 to 12; sums divided by 4 are 4, 8, and 12 You can get this by dice combinations of 1 3 3 1 2 2 4 4 2 6 6 2 3 5 5 3 6 6 That is 9 ways. so odds are 9/36 = 1 in 4
The sums divisible by 3 are 3, 6, 9 and 12. These can be obtained in 2, 5, 4 and 1 ways respectively, giving 2 + 5 + 4 + 1 = 12 ways of success. There are 36 possible ways two dice can fall → probability = ways_of_success/possible_ways = 12/36 = 1/3.
On two fair 6-sided dice: 5 out of 36 = 13.89%. Consider the two dice unique. Maybe one is black with white spots, and the other is white with black spots. There are 36 possible outcomes. You can make a table of the sums, and see that five of the outcomes have a sum of 6. Here they are:1+5, 2+4, 3+3, 4+2, 5+1
Any number between 2 and 12.1+16+6