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Q: How many even sums can you get from rolling two dice?

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The most probable result of rolling two dice is a sum of seven. The probability of rolling a seven is 1 in 6 or about 0.167.All of the other possible sums have decreasing probability, all the way down to 1 in 36 or about 0.0278 for a sum of two or a sum of 12.

216/3 = 72

1 out of 6 * * * * * Total rubbish. There are 11 possible sums - the numbers 2 to 12. So if you throw the dice 12 times, the first 11 can be different but the 12th must be a repeat.

12, because you can only get it one way: 6+6=12 And 2, because get it one way: 1+1=2.

It depends on what you define as an outcome. Let me take a simpler case: just two dice.1. Outcomes of possible sums of the two dice:2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 122. Outcomes of possible sets of two dice:{1, 1}, {1, 2}, {1, 3}, {1, 4}, {1, 5}, {1, 6}, {2, 2}, {2, 3}, {2, 4}, {2, 5}, {2, 6}, {3, 3}, {3, 4}, {3, 5}, {3, 6}, {4, 4}, {4, 5}, {4, 6}, {5, 5}, {5, 6}, {6, 6}3. Outcomes of possible combinations of two dice:(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)We would need to know which you need. Assuming you want all the possible combinations of ten 6-sided dice, then it is 610, or 60,466,176.

Related questions

There are 9 odd sums that you can get from rolling two dice.

The most probable result of rolling two dice is a sum of seven. The probability of rolling a seven is 1 in 6 or about 0.167.All of the other possible sums have decreasing probability, all the way down to 1 in 36 or about 0.0278 for a sum of two or a sum of 12.

216/3 = 72

When rolling 2 dice there are 36 combinations that can occur. Sums will range from 2 to 12; sums divided by 4 are 4, 8, and 12 You can get this by dice combinations of 1 3 3 1 2 2 4 4 2 6 6 2 3 5 5 3 6 6 That is 9 ways. so odds are 9/36 = 1 in 4

5

There are 216 permutations of three dice. Of these, 206 have a sum that is less than 16, specifically, the permutations 466, 556, 565, 566, 646, 655, 656, 664, 665, and 666 have sums that are 16 or greater - all other permutations have sums that are less than 16. The probability, then, of rolling a sum less than 16 on three dice is 206 in 216, or about 0.9537.

The sums divisible by 3 are 3, 6, 9 and 12. These can be obtained in 2, 5, 4 and 1 ways respectively, giving 2 + 5 + 4 + 1 = 12 ways of success. There are 36 possible ways two dice can fall → probability = ways_of_success/possible_ways = 12/36 = 1/3.

There are eleven possible "sums of dots" if you throw two 6-sided dice. The range of possible values is from 2 (1+1) to 12 (6+6).

The set of ordered quintuplets, the set of the sums of the outcomes, the set of the maximum values, the set of the minimum values, the set of the mean values, the set of the ranges, the set of the medians, the set of the differences of the second throw and the fifth. Plus there are very many more options.

On two fair 6-sided dice: 5 out of 36 = 13.89%. Consider the two dice unique. Maybe one is black with white spots, and the other is white with black spots. There are 36 possible outcomes. You can make a table of the sums, and see that five of the outcomes have a sum of 6. Here they are:1+5, 2+4, 3+3, 4+2, 5+1

8 quarters equals 2

No.

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