Listing all possible outcomes:
Dice 1 Dice 2 Sum
1 1 2
1 2 3
1 3 4
1 4 5
1 5 6
1 6 7
2 1 3
2 2 4
2 3 5
2 4 6
2 5 7
2 6 8
3 1 4
3 2 5
3 3 6
3 4 7
3 5 8
3 6 9
4 1 5
4 2 6
4 3 7
4 4 8
4 5 9
4 6 10
5 1 6
5 2 7
5 3 8
5 4 9
5 5 10
5 6 11
6 1 7
6 2 8
6 3 9
6 4 10
6 5 11
6 6 12
Only 3 out of the possible 36 combinations turned out to have a sum of 4. So that is 1/12
The faster mental way:
You know a standard dice has 6 sides.
In this problem, there are two die. So that means you have to multiply 6 x 6. That is 36.
So there are 36 possible outcomes.
You know 1 + 3 = 4, 3 + 1 = 4, and 2 + 2 = 4. Those are the only 3 equations that have all positive numbers that have a sum of 4 (Zero is not positive nor negative).
You have your answer. 3/36. In simplest form, it is 1/12.
The probability of not rolling a sum of six with two fair dice is 1 minus the probability of rolling a sum of six. There are 36 permutations of rolling two dice. Of these, five sum to six, 1+5, 2+4, 3+3, 4+2, and 5+1. The probability, then of rolling a sum of six is 5 in 36. The probability, then of not rolling a sum of six is 31 in 36, or about 0.8611.
Zero is the probability of rolling a sum of 15 on two fair dice; the maximum value is 12.
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
5 in 36
Zero. The minimum value of two dice being rolled is two.
The probability of not rolling a sum of six with two fair dice is 1 minus the probability of rolling a sum of six. There are 36 permutations of rolling two dice. Of these, five sum to six, 1+5, 2+4, 3+3, 4+2, and 5+1. The probability, then of rolling a sum of six is 5 in 36. The probability, then of not rolling a sum of six is 31 in 36, or about 0.8611.
Zero is the probability of rolling a sum of 15 on two fair dice; the maximum value is 12.
The probability of rolling a sum of 11 with 2 dice is: P(11) = 1/18.For explanation see answer to question: "What is the probability of rolling 7 or 11 with 2 dice?".Read more: What_is_the_probability_of_rolling_7_or_11_with_2_dice
Assuming 2 dice, it is 0.
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
5 in 36
Zero. The minimum value of two dice being rolled is two.
The probability is 1, if the dice are rolled often enough.
The probability is 1.
The probability is 29/36.
The probability of rolling a sum of 12 in a single roll of two dice is 1 in 36, or about 0.0278.
The probability of rolling a sum of 8 and doubles when rolling two dice is 1 in 36, or about 0.02778. Simply note that there are 36 permutations of two dice, of which exactly one of them (a 4 and a 4) matches the conditions specified.