Precisely midway. That is to say, at their mean (average).
Assuming it is a function of "x", those are two different names for the same thing.
Exactly halfway
The integral of a given function between given integration limits will always be a constant. The integral of a given function between variable limits - for example, from 0 to x - can only be a constant if the function is equal to zero everywhere.
If it's a straight line, then that's all you need. Find the 'x' and 'y' intercepts,lay your ruler down between the two points, and draw your line.
There is no relationship between the slopes of parallel or perpendicular lines and their y-intercepts.
Assuming it is a function of "x", those are two different names for the same thing.
mwahh
that's true
The vertex must be half way between the two x intercepts
The x co-ordinate of a quadratic lies exactly halfway between the two x-intercepts, assuming they exist. Alternatively, the x co-ordinate can be found using the formula -B/(2A), when the function is in the form, y = Axx + Bx + C.
Exactly halfway
In general, there is no relationship.
You find the intercepts on the x and y axis: First, sub in x=0, giving you y=4. Then sub in y=0, giving you x=-4. So your intercepts are (0,4) and (-4,0). Plot these 2 points, and draw a line between them (you can do this since your function is a straight line, not a curve).
The integral of a given function between given integration limits will always be a constant. The integral of a given function between variable limits - for example, from 0 to x - can only be a constant if the function is equal to zero everywhere.
If it's a straight line, then that's all you need. Find the 'x' and 'y' intercepts,lay your ruler down between the two points, and draw your line.
Measure the distance between the point where the line intercepts the Y axis and the origin
There is no relationship between the slopes of parallel or perpendicular lines and their y-intercepts.