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Q: When you add like terms you to the exponents?
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How do you solve multiplication with like terms?

Just multiply the coefficients, leave the variable the same, and add the exponents.


When you add two terms with different exponential values do you add the exponents together?

No.


When subtracting what to do with the exponents?

It depends on whether you are working with variables. You cannot add terms with variables that have unlike exponents.


How do you multiply and divide numbers with exponents?

If you have like terms then to multiply you add the exponents and to divide you subtract.So, x2 * x3 = x5 and y7 / y5 = y2Also, for example, 2x2 * x3 = 2x5 (we can do this as the terms are like; x's only)But if you do not have like terms then this does not apply.For example, x2 * y3 does not equal xy5.


How do you subtract like variables with different exponents?

You can't. You can only subtract like terms. Like terms must have exactly the same variables and exponents on the variables.


What is terms with the same variables raised to the same exponents?

like terms


What are terms that include the same variables and their corresponding exponents?

like terms


Terms with the same variables raised to the same exponents?

like terms


Algebraic terms that contain the same variables and exponents?

are known as like terms.


When multiplying number do you add the exponents?

If you are multiplying powers of the same base (like 24 times 211), yes, you add the exponents.


When adding numbers with exponents do you add or subtract the exponents?

you do not do anything when you add numbers with exponents. you just figure out the answer. it is only if you multiply numbers with exponents, where you add the exponents..


How do you add polynomials with dissimilar terms?

To add polynomials with dissimilar terms, you simply combine like terms by collecting the terms with the same variables and exponents. If a variable or exponent is not present in one polynomial, you leave it as it is. Then, you can add or subtract the coefficients of the like terms to arrive at your final answer.