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What is the measure of line segment AB if A is 5 and B is 30 degrees?
The question cannot be answered. If AB is a line segment then A and B are normally the end-points of that segment. If A and B are points then A cannot be 5 and B cannot be 30 degrees. If A and B are not end-points of a line segment, it is not at all clear from the question what they are and how they relate to the line segment, AB.
How to prove that three points are collinear by section formula?
Let us understand this concept by taking three points A(2, 5), B(4, 6) and C (8, 8).Now, we have to prove that the points A(2, 5), B(4, 6) and C (8, 8) are Collinear.Let B divides AC in the ratiok: 1Then the coordinates of B will beBut the coordinates of B are (4, 6)Comparing we get⇒8k + 2 = 4k + 4 are 8k + 5 = 6k+ 6⇒8k - 4k = 4 - 2 are 8k - 6k= 6 - 5⇒ 4k = 2 are 2k= 1so here the value of k in both points are same so .....hope u get the answer
What is subtraction of vector quanities?
Vectors are added graphically tip to tail. You subtract vector B from vector A by adding vector -B to vector A. Where -B means a vector that points in the opposite direction as B , but has same magnitude. For example to subtract B (magnitude 4, points left) from vector A (magnitude 3, points up), first draw A, then draw -B (magnitude 4, points right) ,starting -B at the tip of A. Then the vector that connects the tail of A to the tip of -B is the difference A - B or A + (-B) . In this example A & -B form the legs 3 & 4 of a right triangle so the hypotenuse (which is A - B) is 5.
What is the equation of the line that passes through the points negative 2 2 and 0 5?
Just to be clear, the two points are (-2,2) and (0,5). The slope (rise/run) is (5-2)/(0 - -2) = 3/2. So y = (3/2)*x + b. Put one of the point into this and solve for b: 5 = (3/2)*0 + b; b = 5. The equation is y = (3/2)*x + 5. Do a check that the other point (-2,2) satisfies this equation {and it does}.
Three points A B and C which lie on a level plane B is 7 km from A on a bearing of 030 C is 5 km from B on a bearing of 280 what is the distance of AC?
Approx 7.075 km.
What is the measure of line segment AB if A is 5 and B is 30 degrees?
The question cannot be answered. If AB is a line segment then A and B are normally the end-points of that segment. If A and B are points then A cannot be 5 and B cannot be 30 degrees. If A and B are not end-points of a line segment, it is not at all clear from the question what they are and how they relate to the line segment, AB.
What is the slope of the line passing through points A (54) and B(03)?
If you mean points of: (5, 4) and (0, 3) then the slope is 1/5
Points a b c and d are coplanar b c and d are collinear not a how many lines are determined by a b c and d?
5 its 4
What is the slope of the line passing through points A (5,4) and B(0,3)?
1:5
Find the slope of the line that passes through the points A(-2, -1) B(3, 5)?
The slope of a line can be found using the formula: m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are two points on the line. For the line that passes through the points A(-2, -1) and B(3, 5), we have: m = (y2 - y1) / (x2 - x1) = (5 - (-1)) / (3 - (-2)) = 6 / 5 = 1.2 So the slope of the line that passes through the points A(-2, -1) and B(3, 5) is 1.2.
What is the Hp tq 1940 allis chalmers b?
19.5 drawbar hp, 22.25 belt hp.
How to prove that three points are collinear by section formula?
Let us understand this concept by taking three points A(2, 5), B(4, 6) and C (8, 8).Now, we have to prove that the points A(2, 5), B(4, 6) and C (8, 8) are Collinear.Let B divides AC in the ratiok: 1Then the coordinates of B will beBut the coordinates of B are (4, 6)Comparing we get⇒8k + 2 = 4k + 4 are 8k + 5 = 6k+ 6⇒8k - 4k = 4 - 2 are 8k - 6k= 6 - 5⇒ 4k = 2 are 2k= 1so here the value of k in both points are same so .....hope u get the answer
Triangle ABC is reflected over the x-axis. Triangle ABC has points A (10, 2), B (9, 5), and C (6, 4). What is the B' coordinate?
(9, -5)
What is subtraction of vector quanities?
Vectors are added graphically tip to tail. You subtract vector B from vector A by adding vector -B to vector A. Where -B means a vector that points in the opposite direction as B , but has same magnitude. For example to subtract B (magnitude 4, points left) from vector A (magnitude 3, points up), first draw A, then draw -B (magnitude 4, points right) ,starting -B at the tip of A. Then the vector that connects the tail of A to the tip of -B is the difference A - B or A + (-B) . In this example A & -B form the legs 3 & 4 of a right triangle so the hypotenuse (which is A - B) is 5.
How much horsepower does 05 RSX have?
Base model 2005-2006 RSXs have 155 b/hp Base model 2002-2004 RSXs have 160 b/hp 2002-2006 RSX type S have 200 b/hp
What is the equation of the line that passes through the points negative 2 2 and 0 5?
Just to be clear, the two points are (-2,2) and (0,5). The slope (rise/run) is (5-2)/(0 - -2) = 3/2. So y = (3/2)*x + b. Put one of the point into this and solve for b: 5 = (3/2)*0 + b; b = 5. The equation is y = (3/2)*x + 5. Do a check that the other point (-2,2) satisfies this equation {and it does}.
What is the grade equivalence for a 3.29 GPA?
It depends on if the GPA is based on a 5 point scale or a 4 point scale. On a 5 point scale, an A is worth 5 points. On a 4 point scale scale, an A is worth 4 points. So a 3.29 is a B on the 4 point scale and a C on a 5 point scale.
