The slope of a line can be found using the formula:
m = (y2 - y1) / (x2 - x1),
where (x1, y1) and (x2, y2) are two points on the line.
For the line that passes through the points A(-2, -1) and B(3, 5), we have:
m = (y2 - y1) / (x2 - x1) = (5 - (-1)) / (3 - (-2)) = 6 / 5 = 1.2
So the slope of the line that passes through the points A(-2, -1) and B(3, 5) is 1.2.
y=mx+b
No
1
2
1
Not always. For example, try to find the slope of the line that passes through the points (3, 4) and (2, 3).
To find the slope of a line passing through two points, use the formula (y2 - y1) / (x2 - x1). In this case, the two points are (17, 101). Since there is only one given point, it is not possible to find the slope of the line passing through these points.
It is a straight line with no slope with a 'y' intercept of 2
Slope, m, equals (y2-y1)/(x2-x1). Slope is (8-2)/(8-2) or 1.
To find the slope of the line that passes through the points ((a-b)) and ((-a-b)), we first clarify that these points are actually ((a, -b)) and ((-a, -b)). The slope (m) is calculated using the formula (m = \frac{y_2 - y_1}{x_2 - x_1}). Substituting the points, we have (m = \frac{-b - (-b)}{-a - a} = \frac{0}{-2a} = 0). Thus, the slope of the line is 0, indicating a horizontal line.
To find the slope of the line that passes through the points (9, -81) and (6, -36), use the formula for slope ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Plugging in the values, we have ( m = \frac{-36 - (-81)}{6 - 9} = \frac{45}{-3} = -15 ). Thus, the slope of the line is -15.
Slope, m, equals (y2-y1)/(x2-x1). Slope is (0-(-1))/(0-(-1)) or 1/1 or 1.