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Why does cos x equal cos -x?
cos x equals cos -x because cos is an even function. An even function f is such that f(x) = f(-x).
How do you solve triangle EFG given that f equals 15 g equals 18 and f equals 29?
I assume you mean EFG are the interior angles you need to find and efg are the sides( must be sides as they do not add to 180). Use law of cosines. Need to change to your letters; twice. Then for third angle subtract from 180 degrees I assume you mean e = 29 ( you need to be more careful in mathematics ) DEGREE MODE! f^2 = g^2 + e^2 - 2ge cos(F) 15^2 = 18^2 + 29^2 - 2(18)(29) cos(F) 225 = 1165 - 1044(cos F) -940 = -1044(cos F) 0.90038 = cos F arcos(0.90038) = F F = 26 degrees g^2 = e^2 + f^2 - 2ef cos(G) 18^2 = 29^2 + 15^2 - 2(29)(15) cos(G) 324 = 1066 - -870(cos G) -742 = -870(cos G) 0.85287 = cos G arcos(0.85287) = G G = 31 degrees Now just subtract these answers from 180 degrees for E 180 - 26 - 31 E = 123 degrees F = 26 degrees G = 31 degrees
If fx equals cossinx2 then f prime equals?
f(x)=cos(sin(x2)) [u(v)]' = u'(v) * v' so f'(x) = cos'(sinx(x2)) * sin'(x2) * (x2)' f'(x) = -sin(sin(x2)) * cos(x2) * 2x = -2x sin(sin(x2)) cos(x2)
What is the derivative of 6 sin x plus 2 cos x?
F(x) = 6 sin(x) + 2 cos(x)F'(x) = 6 cos(x) - 2 sin(x)
How do you differentiate cos x all squared?
If this is a homework assignment, please consider trying to answer it yourself first, otherwise the value of the reinforcement of the lesson offered by the assignment will be lost on you.The deriviative d/dx cos2(x) can be evaluated using the product rule.Recall that d/dx f(x)g(x) = g(x) d/dx f(x) + f(x) d/dx g(x)In this case, both f(x) and g(x) are cos(x), and cos2x = cos(x)cos(x), so...d/dx cos(x)cos(x) = -cos(x)sin(x) - cos(x)sin(x) = -2sin(x)cos(x)
