f(x)=cos(sin(x2))
[u(v)]' = u'(v) * v'
so f'(x) = cos'(sinx(x2)) * sin'(x2) * (x2)'
f'(x) = -sin(sin(x2)) * cos(x2) * 2x = -2x sin(sin(x2)) cos(x2)
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3
fx=3x-5 f=(3x-5)/x f2=(6x-10)/x /=divide
3
Are you trying to solve for x? Fx = x2 - 3 x2 - Fx - 3 = 0 x2 - Fx = 3 x2 - Fx + (F/2)2 = 3 + (F/2)2 (x - F/2)2 = 3 + (F/2)2 x - F/2 = ±[ 3 + (F/2)2 ]1/2 x = F/2 ± [ 3 + (F/2)2 ]1/2
If you are talking about f(x) then yes it is the same as y