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Is the given point interior exterior or on the circle x 22 y - 32 81?
To determine if the point (22, -32) is interior, exterior, or on the circle defined by the equation (x^2 + y^2 = 81), we first calculate the distance from the point to the center of the circle, which is at the origin (0, 0). The distance is given by (d = \sqrt{22^2 + (-32)^2} = \sqrt{484 + 1024} = \sqrt{1508} \approx 38.8). Since the radius of the circle is 9 (since (81 = 9^2)), and (38.8) is greater than (9), the point (22, -32) is located outside the circle.
Where is the center of the circle given by the equation x plus 52 plus y-32 equals 56?
There need to be squares in there for x and y - I think you're asking for the centre of the circle with equation: (x + 5)2 + (y - 3)2 = 56 in which case the centre is (-5, 3) A circle with centre (xo, yo) and radius r has equation of the form: (x - xo)2 + (y - yo)2 = r2
What is a result of shifting a circle with equation x 32 y - 22 36 left 3 units?
Shifting the circle with the equation ( x^2 + y^2 - 22x - 36 = 0 ) left by 3 units involves adjusting the ( x ) coordinate in the equation. The new equation becomes ( (x + 3)^2 + y^2 - 22(x + 3) - 36 = 0 ). This results in a new center for the circle, which is now located at ( (19, 0) ) instead of ( (22, 0) ), while the radius remains unchanged. Thus, the overall shape and size of the circle do not change, only its position.
How do you write the sum of -47 and 15 is -32 as an equation?
You can write the sum of -47 and 15 is -32 as an equation like this: -47 + 15 = -32. This equation states that when you add -47 and 15 together, the result is -32.
How do you find celsius when given only Fahrenheit?
You can use this equation to convert degrees Fahrenheit (ºF) to degrees Celsius (ºC): [°C] = ([°F] − 32) × 5⁄9
What is the equation of the circle with center (32) and radius 4.3?
It is: (x-3)^2 +(y -2)^2 = 18.49
Is the given point interior exterior or on the circle x 22 y - 32 81?
To determine if the point (22, -32) is interior, exterior, or on the circle defined by the equation (x^2 + y^2 = 81), we first calculate the distance from the point to the center of the circle, which is at the origin (0, 0). The distance is given by (d = \sqrt{22^2 + (-32)^2} = \sqrt{484 + 1024} = \sqrt{1508} \approx 38.8). Since the radius of the circle is 9 (since (81 = 9^2)), and (38.8) is greater than (9), the point (22, -32) is located outside the circle.
Where is the center of the circle given by the equation x plus 52 plus y-32 equals 56?
There need to be squares in there for x and y - I think you're asking for the centre of the circle with equation: (x + 5)2 + (y - 3)2 = 56 in which case the centre is (-5, 3) A circle with centre (xo, yo) and radius r has equation of the form: (x - xo)2 + (y - yo)2 = r2
What is the standard form of an equation were the poin 3-6 is on a circle whose orgin is the center?
32+62=45 so the standard form is x2+y2=45
What is a result of shifting a circle with equation x 32 y - 22 36 left 3 units?
Shifting the circle with the equation ( x^2 + y^2 - 22x - 36 = 0 ) left by 3 units involves adjusting the ( x ) coordinate in the equation. The new equation becomes ( (x + 3)^2 + y^2 - 22(x + 3) - 36 = 0 ). This results in a new center for the circle, which is now located at ( (19, 0) ) instead of ( (22, 0) ), while the radius remains unchanged. Thus, the overall shape and size of the circle do not change, only its position.
What is the center and radius of a circle with an equation of x squared plus y squared - 10x plus 6y equals 47?
The equation of the circle with center (h, k) and radius r is of the form(x - h)2 + (y - k)2 = r2x2 + y2 - 10x + 6y = 47 (complete the square)[x2 - 10x + (10/2)2] + [y2 + 6y +(6/2)2] = 47 + (10/2)2 +(6/2)2(x2 - 10x + 52) + (y2 + 6y + 32) = 47 + 52 + 32(x - 5)2 + (y + 3)2 = 81(x - 5)2 + (y + 3)2 = 92So that the center of the circle is (5, -3) and the radius is 9.
How do you get the square footage of a 32 foot circle?
We have to guess at what the question means where it says a "32 foot circle".-- Is the circle 32 feet in diameter . . . across the widest part ?-- Is it 32 feet in radius . . . from the center to the curve ??-- Is it 32 feet in circumference . . . around the curve ???We'll assume it's 32 feet in "diameter" ... across the 'widest' part.The area of a circle is [ pi R2 ] where 'R' = the radius = 1/2 of the diameter.pi R2 = pi (32/2)2 = pi (16)2 = 256 pi = 804.25 square feet (rounded)
What is the circumference of a circle with 32 diameter?
The circumference of a circle with 32 diameter is: 100.53 units.
How do you write the sum of -47 and 15 is -32 as an equation?
You can write the sum of -47 and 15 is -32 as an equation like this: -47 + 15 = -32. This equation states that when you add -47 and 15 together, the result is -32.
What is the area of a 32 inch circle?
A 32-inch circle has an area of 804 square inches.
What is the circumference of the circle if the circle is 32 inches in diameter?
A circle with a radius of 16 inches (32/2) has a circumference of 100.53 inches.
What is the equation for this answer n equals -32?
n=-32
