From the information given the circle centre is (-4,3).
Since no sign is given with '4' , it is assumed it is positive.
The '= 4' is radius squared (Pythagoras).
So the whole equation becomes
(x --4)^2 + (y - 3)^2= 4 = 2^2 =>
( x + 4)^2 + ( y - 3)^2 = 2^2 (Note the Pythagorean equation).
Multiply out
x^2 + 8x + 16 + y^2 - 6y + 9 = 4
Collect terms
x^2 + y^2 + 8x - 6y + 21 = 0
The equation of the given circle.
(-4,-6)
The centre is (-5, 3)
The equation describes a circle with its centre at the origin and radius = √13. Each and every point on that circle is a solution.
no
x2 + y2 = 49
The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).
(-4,-6)
You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)
The centre is (-5, 3)
The equation describes a circle with its centre at the origin and radius = √13. Each and every point on that circle is a solution.
no
I think this means (x+7)squared + (y-5)squared =4squared, which represents a circle centred at -7,+5
Relationship between circle are and radius squa0red is A(Area) = pi r^2(radius squared). pi is the constant of proportionality for ALL circles . It has a value of 3.141592..... However for elementary school work , pi = 3.14 NB Remember to other relationship with circles for circumference. C = 2 pi r = pi d Learn and commit to memory ;- A = pi r^2 & C = 2 pi r
x2 + y2 = 49
No. C = 2*pi*r is the equation representing the circumference of a circle. The area of a circle is equal to pi*(r^2).
Area of a circle equals pi (~3.14) multiplied by the radius squared. So to find the area of that circle your equation is (3.14)(3)^2 which equals approximately 27.
56