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From the information given the circle centre is (-4,3).
Since no sign is given with '4' , it is assumed it is positive.
The '= 4' is radius squared (Pythagoras).
So the whole equation becomes
(x --4)^2 + (y - 3)^2= 4 = 2^2 =>
( x + 4)^2 + ( y - 3)^2 = 2^2 (Note the Pythagorean equation).
Multiply out
x^2 + 8x + 16 + y^2 - 6y + 9 = 4
Collect terms
x^2 + y^2 + 8x - 6y + 21 = 0
The equation of the given circle.
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Where is the center of the circle given by the equation x plus 4 squared plus y plus 6 squared equals 49?
(-4,-6)
Where is the center of the circle given by the equation x plus 5 squared plus y minus 3 squared equals 25?
The centre is (-5, 3)
How do you solve x squared plus y squared equals 13?
The equation describes a circle with its centre at the origin and radius = √13. Each and every point on that circle is a solution.
Does the equation a squared plus b squared equals c squared classify as a quadratic equation?
no
What is the equation for a circle with its center at the origin and a tangent whose equation is y equals 7?
x2 + y2 = 49
Where is the center of the circle given by the equation x - 3 squared plus y plus 2 squared equals 9?
The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).
Where is the center of the circle given by the equation x plus 4 squared plus y plus 6 squared equals 49?
(-4,-6)
How do you graph the equation x squared plus y squared equals 16?
You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)
Where is the center of the circle given by the equation x plus 5 squared plus y minus 3 squared equals 25?
The centre is (-5, 3)
How do you solve x squared plus y squared equals 13?
The equation describes a circle with its centre at the origin and radius = √13. Each and every point on that circle is a solution.
Does the equation a squared plus b squared equals c squared classify as a quadratic equation?
no
Where is the center of the circle given by the equation x plus 7 2 plus y - 5 2 equals 16 Enter your answer as an ordered pair?
I think this means (x+7)squared + (y-5)squared =4squared, which represents a circle centred at -7,+5
What is the relationship between the area of a circle and its radius squared?
Relationship between circle are and radius squa0red is A(Area) = pi r^2(radius squared). pi is the constant of proportionality for ALL circles . It has a value of 3.141592..... However for elementary school work , pi = 3.14 NB Remember to other relationship with circles for circumference. C = 2 pi r = pi d Learn and commit to memory ;- A = pi r^2 & C = 2 pi r
What is the equation for a circle with its center at the origin and a tangent whose equation is y equals 7?
x2 + y2 = 49
Is c equals 2πr the same as c equals πr squared?
No. C = 2*pi*r is the equation representing the circumference of a circle. The area of a circle is equal to pi*(r^2).
What is the approximate area of a circle with a radius of 3 feet?
Area of a circle equals pi (~3.14) multiplied by the radius squared. So to find the area of that circle your equation is (3.14)(3)^2 which equals approximately 27.
What is the center of a circle for the equation 3x2 plus 3y2 - 30x plus 27 equals 0?
56
