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From the information given the circle centre is (-4,3).

Since no sign is given with '4' , it is assumed it is positive.

The '= 4' is radius squared (Pythagoras).

So the whole equation becomes

(x --4)^2 + (y - 3)^2= 4 = 2^2 =>

( x + 4)^2 + ( y - 3)^2 = 2^2 (Note the Pythagorean equation).

Multiply out

x^2 + 8x + 16 + y^2 - 6y + 9 = 4

Collect terms

x^2 + y^2 + 8x - 6y + 21 = 0

The equation of the given circle.

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Q: Where is the center of the circle given by the equation x 4 squared y - 3 squared equals 4?

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(-4,-6)

The centre is (-5, 3)

The equation describes a circle with its centre at the origin and radius = âˆš13. Each and every point on that circle is a solution.

no

x2 + y2 = 49

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The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).

(-4,-6)

You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)

The centre is (-5, 3)

The equation describes a circle with its centre at the origin and radius = âˆš13. Each and every point on that circle is a solution.

no

I think this means (x+7)squared + (y-5)squared =4squared, which represents a circle centred at -7,+5

Relationship between circle are and radius squa0red is A(Area) = pi r^2(radius squared). pi is the constant of proportionality for ALL circles . It has a value of 3.141592..... However for elementary school work , pi = 3.14 NB Remember to other relationship with circles for circumference. C = 2 pi r = pi d Learn and commit to memory ;- A = pi r^2 & C = 2 pi r

x2 + y2 = 49

No. C = 2*pi*r is the equation representing the circumference of a circle. The area of a circle is equal to pi*(r^2).

Area of a circle equals pi (~3.14) multiplied by the radius squared. So to find the area of that circle your equation is (3.14)(3)^2 which equals approximately 27.

56

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