when the function is in vertex form: y = a(x - h)2 + k, the point (h, k) is the vertex.
The vertex of a parabola doe not provide enough information to graph anything - other than the vertex!
The vertex is either the minimum (very bottom) or maximum (very top) of a parabola.
right
Above
A quadratic equation in vertex form is expressed as ( y = a(x - h)^2 + k ), where ((h, k)) is the vertex of the parabola. For a parabola with vertex at ((11, -6)), the equation becomes ( y = a(x - 11)^2 - 6 ). The value of (a) determines the direction and width of the parabola. Without additional information about the parabola's shape, (a) can be any non-zero constant.
The vertex would be the point where both sides of the parabola meet.
To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the right of the vertex.
The vertex of a parabola doe not provide enough information to graph anything - other than the vertex!
The vertex is either the minimum (very bottom) or maximum (very top) of a parabola.
the vertex of a parabola is the 2 x-intercepts times-ed and then divided by two (if there is only 1 x-intercept then that is the vertex)
The vertex -- the closest point on the parabola to the directrix.
i think that the range and the domain of a parabola is the coordinates of the vertex
A parabola's maximum or minimum is its vertex.
Above
right
A quadratic equation in vertex form is expressed as ( y = a(x - h)^2 + k ), where ((h, k)) is the vertex of the parabola. For a parabola with vertex at ((11, -6)), the equation becomes ( y = a(x - 11)^2 - 6 ). The value of (a) determines the direction and width of the parabola. Without additional information about the parabola's shape, (a) can be any non-zero constant.
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