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A quadratic equation in vertex form is expressed as ( y = a(x - h)^2 + k ), where ((h, k)) is the vertex of the parabola. For a parabola with vertex at ((11, -6)), the equation becomes ( y = a(x - 11)^2 - 6 ). The value of (a) determines the direction and width of the parabola. Without additional information about the parabola's shape, (a) can be any non-zero constant.

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Which equation describes a parabola that opens up or down and whose vertex is at the point (h v)?

The equation that describes a parabola that opens up or down with its vertex at the point (h, v) is given by the vertex form of a quadratic equation: ( y = a(x - h)^2 + v ), where ( a ) determines the direction and width of the parabola. If ( a > 0 ), the parabola opens upwards, while if ( a < 0 ), it opens downwards.


How do you rewrite the equation of a parabola in standard form?

To rewrite the equation of a parabola in standard form, you need to express it as ( y = a(x - h)^2 + k ) for a vertically oriented parabola or ( x = a(y - k)^2 + h ) for a horizontally oriented parabola. Here, ( (h, k) ) represents the vertex of the parabola, and ( a ) determines its direction and width. You can achieve this by completing the square on the quadratic expression.


How do you find the a value in a parabola?

To find the "a" value in a parabola, which determines its width and direction (opening upwards or downwards), you can use the standard form of a quadratic equation: (y = ax^2 + bx + c). If you have a specific point on the parabola and the values of (b) and (c), you can substitute these into the equation along with the coordinates of the point to solve for (a). Alternatively, if the parabola is in vertex form, (y = a(x-h)^2 + k), you can derive (a) using the vertex and another point on the curve.


What is the vertex of a parabola that opens down called?

The vertex of a parabola that opens down is called the maximum point. This point represents the highest value of the function described by the parabola, as the graph decreases on either side of the vertex. In a quadratic equation of the form (y = ax^2 + bx + c) where (a < 0), the vertex can be found using the formula (x = -\frac{b}{2a}). The corresponding (y)-value can then be calculated to determine the vertex's coordinates.


How do you get directrix of a parabola?

The directrix of a parabola can be found using its standard form equation. For a parabola that opens upwards or downwards, given by (y = ax^2 + bx + c), the directrix is located at (y = k - \frac{1}{4p}), where (k) is the vertex's y-coordinate and (p) is the distance from the vertex to the focus. For a parabola that opens sideways, the directrix is given by (x = h - \frac{1}{4p}), where (h) is the vertex's x-coordinate. The value of (p) can be determined based on the coefficients of the quadratic equation.

Related Questions

What different information do you get from vertex form and quadratic equation in standard form?

The graph of a quadratic function is always a parabola. If you put the equation (or function) into vertex form, you can read off the coordinates of the vertex, and you know the shape and orientation (up/down) of the parabola.


What is the equation for vertex form?

The vertex form for a quadratic equation is y=a(x-h)^2+k.


The vertex of the parabola below is at the point (-4-2) which equation below could be one for parabola?

-2


What is the standard form for a quadratic equation?

Normally a quadratic equation will graph out into a parabola. The standard form is f(x)=a(x-h)2+k


In a parabola equation what are you looking for?

An equation that when plotted produces a parabola is a quadratic equation of the form y = ax2 + bx + c where a, b and c are constants.


How do you rewrite the equation of a parabola in standard form?

To rewrite the equation of a parabola in standard form, you need to express it as ( y = a(x - h)^2 + k ) for a vertically oriented parabola or ( x = a(y - k)^2 + h ) for a horizontally oriented parabola. Here, ( (h, k) ) represents the vertex of the parabola, and ( a ) determines its direction and width. You can achieve this by completing the square on the quadratic expression.


The vertex of the parabola below is at the point (5 -3). Which of the equations below could be the one for this parabolaus anything?

To determine the equation of a parabola with a vertex at the point (5, -3), we can use the vertex form of a parabola's equation: (y = a(x - h)^2 + k), where (h, k) is the vertex. Substituting in the vertex coordinates, we have (y = a(x - 5)^2 - 3). The value of "a" will determine the direction and width of the parabola, but any equation in this form with varying "a" values could represent the parabola.


How do you find the a value in a parabola?

To find the "a" value in a parabola, which determines its width and direction (opening upwards or downwards), you can use the standard form of a quadratic equation: (y = ax^2 + bx + c). If you have a specific point on the parabola and the values of (b) and (c), you can substitute these into the equation along with the coordinates of the point to solve for (a). Alternatively, if the parabola is in vertex form, (y = a(x-h)^2 + k), you can derive (a) using the vertex and another point on the curve.


What is the vertex of a parabola that opens down called?

The vertex of a parabola that opens down is called the maximum point. This point represents the highest value of the function described by the parabola, as the graph decreases on either side of the vertex. In a quadratic equation of the form (y = ax^2 + bx + c) where (a < 0), the vertex can be found using the formula (x = -\frac{b}{2a}). The corresponding (y)-value can then be calculated to determine the vertex's coordinates.


How do you get directrix of a parabola?

The directrix of a parabola can be found using its standard form equation. For a parabola that opens upwards or downwards, given by (y = ax^2 + bx + c), the directrix is located at (y = k - \frac{1}{4p}), where (k) is the vertex's y-coordinate and (p) is the distance from the vertex to the focus. For a parabola that opens sideways, the directrix is given by (x = h - \frac{1}{4p}), where (h) is the vertex's x-coordinate. The value of (p) can be determined based on the coefficients of the quadratic equation.


What is an equation of the parabola in vertex form that passes through (13 8) and has vertex (3 2).?

please help


What is the difference between linear and quadratic equations?

A linear equation has the form of mx + b, while a quadratic equation's form is ax2+bx+c. Also, a linear equation's graph forms a line, while a quadratic equation's graph forms a parabola.