0
Set to 0.
X^2 - 6X + 12 = 0
X^2 - 6X = -12
halve the linear term (-6), square it and add it to both sides
X^2 - 6X + 9 = -12 + 9
gather terms right side, factor terms left side
(X - 3)^2 = -3
(X - 3)^2 + 3 = 0
(3,3) are the vector coordinates
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What is Y equals 2xsquared-12x plus 6?
"y = 2x2 - 12x + 6" is a quadratic equation which describes a parabola whose vertex occurs at the point (3, -12) and which has a range of -12 → ∞. It intercepts the x-axis at the points (3 - √6, 0) and (3 + √6, 0).
Find the x-coordinate of the vertex of this parabola fx equals xsquared plus 6x-2?
4
What is 12 plus 9 equals?
12 plus 9 equals 21.
Determine the graph of the quadratic function y equals 8x2 plus 10x plus 3?
i am 12 and the answer is:The vertex is: -5/8, 7/8X intercepts are: -3/8 AND -12 7/8* * *I believe the following answers will be found correct:y = 8x2 + 10x + 3 = (4x + 3)(2x + 1).The x-intercepts occur at x = -¾ and x = -½.The vertex occurs at x = -5/8, y = (-5/2 + 3)(-5/4 + 1) = (1/2)(-1/4) = -1/8;that is, at (-5/8, -1/8).The parabola is, of course, concave-upwards.
12 plus 10 plus 11 equals?
12 + 10 + 11 equals 33
What is Y equals 2xsquared-12x plus 6?
"y = 2x2 - 12x + 6" is a quadratic equation which describes a parabola whose vertex occurs at the point (3, -12) and which has a range of -12 → ∞. It intercepts the x-axis at the points (3 - √6, 0) and (3 + √6, 0).
Find the x-coordinate of the vertex of this parabola fx equals xsquared plus 6x-2?
4
How do you find the vertex of the parabola 3x squared -x plus 4?
7
Find equation what parabola its vertex is 0 0 and it passes through point 2 12 express the equation in standard form?
Y=3x^2 and this is in standard form. The vertex form of a prabola is y= a(x-h)2+k The vertex is at (0,0) so we have y=a(x)^2 it goes throug (2,12) so 12=a(2^2)=4a and a=3. Now the parabola is y=3x^2. Check this: It has vertex at (0,0) and the point (2,12) is on the parabola since 12=3x2^2
What does 12 plus 12 plus 12 plus 12 plus 12 plus 12 equals?
it equals 72. just do 12 X 6
What is the x-coordinate of the of the vertex of y equals -3x2 plus 12x-5?
You can find the x-coordinate of it's vertex by taking it's derivative and solving for zero: y = -3x2 + 12x - 5 y' = -6x + 12 0 = -6x + 12 6x = 12 x = 2 Now that we have it's x coordinate, we can plug it back into the original equation to find it's y coordinate: y = -3x2 + 12x - 5 y = -3(2)2 + 12(2) + 5 y = -12 + 24 + 5 y = 17 So the vertex of the parabola y = -3x2 + 12x - 5 occurs at the point (2, 17).
What is 6 plus 12 plus 12 plus 16 plus 24 equals?
it equals 70
What is 12 plus 9 equals?
12 plus 9 equals 21.
What is y equals 2xsquared-5x -12 in vertex form?
The curve turns at a minimum: (2.5, -12)
What is the vertex of the parabola y equals -2x squared plus 12x -13?
There are two forms in which a quadratic equation can be written: general form, which is ax2 + bx + c, and standard form, which is a(x - q)2 + p. In standard form, the vertex is (q, p). So to find the vertex, simply convert general form into standard form.The formula often used to convert between these two forms is:ax2 + bx + c = a(x + b/2a)2 + c - b2/4aSubstitute the variables:-2x2 + 12x - 13 = -2(x + 12/-4)2 -13 + 122/-8-2x2 + 12x - 13 = -2(x - 3)2 + 5Since the co-ordinates of the vertex are equal to (q, p), the vertex of the parabola defined by the equation y = -2x2 + 12x - 13 is located at point (3, 5)
Determine the graph of the quadratic function y equals 8x2 plus 10x plus 3?
i am 12 and the answer is:The vertex is: -5/8, 7/8X intercepts are: -3/8 AND -12 7/8* * *I believe the following answers will be found correct:y = 8x2 + 10x + 3 = (4x + 3)(2x + 1).The x-intercepts occur at x = -¾ and x = -½.The vertex occurs at x = -5/8, y = (-5/2 + 3)(-5/4 + 1) = (1/2)(-1/4) = -1/8;that is, at (-5/8, -1/8).The parabola is, of course, concave-upwards.
plus plus equals 24?
12+12
