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If a point has an abscissa of 5, it means that its x-coordinate is 5. The point could lie anywhere along the vertical line where x equals 5, which extends infinitely in the positive and negative directions on the y-axis. Therefore, the point could be represented as (5, y), where y can be any real number.

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AnswerBot

1mo ago

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Related Questions

Where would a point lie if its ordinate is 5 and if its abscissa is -4?

IV


What is the abscissa of all the points in the y-axis?

the abscissa of the point -2 -5 is


Where on the coordinate plane would point (0-5) Lie?

It would lie on the y axis


Where on the coordinate plane would point (0 -5) lie?

5


Where on th coordinate plane would point (0-5) lie?

5


In this pair 4 -5 which number is the abscissa?

9


In this ordered pair (4 -5) which number is the abscissa?

It is 4.


Does the point (-4,1) lie on the line y=-x+5?

y = -x + 5 Substitute ( -4,1) 1 = --4 + 5 1 = 4 + 5 = 9 Simce it doesn't equate, then the point does NOT lie on the line.


What numbers lie between 4 and 5 on the number line?

All numbers that have a 4 before a decimal point and some non-zero digits after the decimal point lie between 4 and 5. If the "between" is inclusive, then the numbers 4 and 5 (which can be followed by a decimal point and any number of zeros) also lie there.


What point lies on the line y plus 5 equals 2x-10?

An infinite number of points lie on that line. One such would be (40, 65).


What is the product of abscissa and ordinate is ten?

The product of the abscissa (x-coordinate) and the ordinate (y-coordinate) being ten means that for any point ((x, y)) on the Cartesian plane, the equation (x \cdot y = 10) holds true. This relationship describes a hyperbola in the xy-plane, where the coordinates can take on various pairs of values (e.g., ((1, 10)), ((2, 5)), ((5, 2)), ((10, 1)), etc.). Each pair represents a point where the product of the x and y values equals ten.


Which of the following points does NOT lie on the graph of the following equation 5x plus 6y equals -3?

Since no points were given, for any point (x,y), plug the x and y values of the point into the equation. If you get a contradiction, ie 5=3 or something similar, then the point does not lie on the graph.