There are an infinite number of pairs of numbers that when multiplied together produce 120. If the question refers to the length and width of the rectangle being integers then the solutions are the paired factors of 120. 1, 120 : 2, 60 : 3, 40 : 4, 30 : 5, 24 : 6, 20 : 8, 15 and 10, 12. There are therefore 8 pairs if the distinction between length and width is not relevant, but there are 16 pairs (the above pairs plus the same numbers in reverse order) if the distinction is important.
x=1, y=0 or you could do: x=2. y=5 there are basically endless possibilties
Start by factoring the number. 2500 = 2 X 2 X 5 X 5 X 5 X 5 The answer is 3. Explanation: There is one pair of 2's and two pairs of 5's that go into the number.
Any pair of numbers where the 'y' is 5 more than the 'x'. There are an infinite number of suitable pairs.
5 - 3 = 2
There are infinitely many possible pairs. Some pairs are: 1 and 500 1000 and 1/2 sqrt(5) and 100sqrt(5)
The answer is - not are : (5, 1).
4
no real solutions
The factor pairs of 25 are 1 x 25 and 5 x 5
They are 2 and 5
sp3d hybridization for 5 electron pairs (2 lone pairs and 3 bonded pairs).
2, 10 5, 10
The factor pairs of 10 are 1*10, 2*5
2 and 5 5 and 10
2 + 3 2 + 5 2 + 9 2 + 11
5