The equation (3x + 8 = 3x - 5) has no solutions because when you simplify it, you end up with (8 = -5), which is a contradiction. This means there are no values of (x) that can satisfy the equation, indicating that the two sides are never equal. Thus, the equation is inconsistent and has no solution.
The equation (3x + 8 = 3x - 5) has no solutions because when we attempt to isolate (x), we end up with a contradiction. Subtracting (3x) from both sides results in (8 = -5), which is not true. Since there are no values of (x) that can satisfy this equation, it has no solutions.
The equation (3x + 8 = 3x - 5) has no solutions because when you simplify it, you subtract (3x) from both sides, resulting in (8 = -5). This statement is false, as 8 does not equal -5. Since the equation leads to a contradiction, it indicates that there are no values of (x) that can satisfy it. Thus, the equation has no solutions.
If you mean: y = 15+3x then it is the function of a straight line equation.
There are none because without an equality sign it can not be considered to be an equation and the + or - values of 3x and 10 are not given
An algebraic equation with an infinite number of solutions
The equation (3x + 8 = 3x - 5) has no solutions because when we attempt to isolate (x), we end up with a contradiction. Subtracting (3x) from both sides results in (8 = -5), which is not true. Since there are no values of (x) that can satisfy this equation, it has no solutions.
The equation (3x + 8 = 3x - 5) has no solutions because when you simplify it, you subtract (3x) from both sides, resulting in (8 = -5). This statement is false, as 8 does not equal -5. Since the equation leads to a contradiction, it indicates that there are no values of (x) that can satisfy it. Thus, the equation has no solutions.
If you mean: y = 15+3x then it is the function of a straight line equation.
There are none because without an equality sign it can not be considered to be an equation and the + or - values of 3x and 10 are not given
An algebraic equation with an infinite number of solutions
How many solutions are there to the equation below? 3x-10(x+2) = 13-7x 0
One.
None because without an equal sign it's not an equation
If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7
There are no real solutions because the discriminant of the quadratic equation is less than zero.
They are x = -1 and x = 4.
one