There are none because without an equality sign it can not be considered to be an equation and the + or - values of 3x and 10 are not given
An algebraic equation with an infinite number of solutions
4x2+3x+6+5x+3x+6 = 4x2+11x+12 when simplified
One.
From first equation y = 3x + 5. Substitute this in second equation 2(3x + 5) = 6x + 10 This proves that 6x + 10 = 6x + 10 which is not helpful! I suppose possible solutions would be x = 0, y = 5 or x = 1, y = 8 etc etc Are you sure of your two equations, please?
None because without an equal sign it's not an equation
There are infinitely many solutions to the equation since it simplifies to 13 = 13, which is always true.
Quadratic equation formula
None because without an equality sign it cannot be an equation
x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0
NO,because in quadratic equation highest power of a variable is 2. e.x. 4x2-20x+10=0.
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
y=4x2+3x+8
An algebraic equation with an infinite number of solutions
4x2 - 3x - 9
(3x + 2)(x - 5) = 0 x = -2/3 or 5
4x2+3x+6+5x+3x+6 = 4x2+11x+12 when simplified
3x+10=12x-17