There are none because without an equality sign it can not be considered to be an equation and the + or - values of 3x and 10 are not given
The equation (3x + 8 = 3x - 5) has no solutions because when you simplify it, you subtract (3x) from both sides, resulting in (8 = -5). This statement is false, as 8 does not equal -5. Since the equation leads to a contradiction, it indicates that there are no values of (x) that can satisfy it. Thus, the equation has no solutions.
The equation (3x + 8 = 3x - 5) has no solutions because when we attempt to isolate (x), we end up with a contradiction. Subtracting (3x) from both sides results in (8 = -5), which is not true. Since there are no values of (x) that can satisfy this equation, it has no solutions.
The equation (3x + 8 = 3x - 5) has no solutions because when you simplify it, you end up with (8 = -5), which is a contradiction. This means there are no values of (x) that can satisfy the equation, indicating that the two sides are never equal. Thus, the equation is inconsistent and has no solution.
An algebraic equation with an infinite number of solutions
4x2+3x+6+5x+3x+6 = 4x2+11x+12 when simplified
How many solutions are there to the equation below? 3x-10(x+2) = 13-7x 0
Quadratic equation formula
The equation (3x + 8 = 3x - 5) has no solutions because when you simplify it, you subtract (3x) from both sides, resulting in (8 = -5). This statement is false, as 8 does not equal -5. Since the equation leads to a contradiction, it indicates that there are no values of (x) that can satisfy it. Thus, the equation has no solutions.
None because without an equality sign it cannot be an equation
The equation (3x + 8 = 3x - 5) has no solutions because when we attempt to isolate (x), we end up with a contradiction. Subtracting (3x) from both sides results in (8 = -5), which is not true. Since there are no values of (x) that can satisfy this equation, it has no solutions.
x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0
NO,because in quadratic equation highest power of a variable is 2. e.x. 4x2-20x+10=0.
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
y=4x2+3x+8
An algebraic equation with an infinite number of solutions
4x2 - 3x - 9
(3x + 2)(x - 5) = 0 x = -2/3 or 5