There are none because without an equality sign it can not be considered to be an equation and the + or - values of 3x and 10 are not given
The equation (3x + 8 = 3x - 5) has no solutions because when you simplify it, you subtract (3x) from both sides, resulting in (8 = -5). This statement is false, as 8 does not equal -5. Since the equation leads to a contradiction, it indicates that there are no values of (x) that can satisfy it. Thus, the equation has no solutions.
The equation (3x + 8 = 3x - 5) has no solutions because when we attempt to isolate (x), we end up with a contradiction. Subtracting (3x) from both sides results in (8 = -5), which is not true. Since there are no values of (x) that can satisfy this equation, it has no solutions.
An algebraic equation with an infinite number of solutions
4x2+3x+6+5x+3x+6 = 4x2+11x+12 when simplified
One.
How many solutions are there to the equation below? 3x-10(x+2) = 13-7x 0
Quadratic equation formula
None because without an equality sign it cannot be an equation
x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0
NO,because in quadratic equation highest power of a variable is 2. e.x. 4x2-20x+10=0.
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
y=4x2+3x+8
An algebraic equation with an infinite number of solutions
4x2 - 3x - 9
(3x + 2)(x - 5) = 0 x = -2/3 or 5
3x+10=12x-17
4x2+3x+6+5x+3x+6 = 4x2+11x+12 when simplified