One.
one
x2+3x+8 is a trinomial But this quadratic equation will have no solutions because its discriminant is less than zero.
Balance the equation out....3x + 5 - 8 = 303x + (-3) = 303x - 3 = 303x = 30 + 33x = 333x / 3 = 33 / 3x = 11
From first equation y = 3x + 5. Substitute this in second equation 2(3x + 5) = 6x + 10 This proves that 6x + 10 = 6x + 10 which is not helpful! I suppose possible solutions would be x = 0, y = 5 or x = 1, y = 8 etc etc Are you sure of your two equations, please?
One.
one
3x + 2y = 8 This is an equation. It could be the equation of a line.
Without an equality sign the given terms can't be considered to be an equation and so therefore no solutions are possible.
x2+3x+8 is a trinomial But this quadratic equation will have no solutions because its discriminant is less than zero.
If you mean 2x^2 -3x +8 = 0 then the discriminant works out as -55 which is less than 0 meaning that the equation has no real roots and so therefore no solutions are possible.
Balance the equation out....3x + 5 - 8 = 303x + (-3) = 303x - 3 = 303x = 30 + 33x = 333x / 3 = 33 / 3x = 11
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From first equation y = 3x + 5. Substitute this in second equation 2(3x + 5) = 6x + 10 This proves that 6x + 10 = 6x + 10 which is not helpful! I suppose possible solutions would be x = 0, y = 5 or x = 1, y = 8 etc etc Are you sure of your two equations, please?
your equation is y=3x + 4 here are five parallel equations... y=3x + 5 y=3x + 6 y=3x + 7 y=3x + 8 y=3x + 9
8X + 4 = 3X + 8 subtract 3X from both sides of equation 5X + 4 = 8 subtract 4 from both sides equation 5X = 4 divide both sides integers by 5 X = 4/5 -------------------check in original equation 8(4/5) + 4 = 3(4/5) + 8 32/5 + 4 = 12/5 + 8 now, 4 = 20/5 and 8 = 40/5, so 32/5 + 20/5 = 12/5 + 40/5 52/5 = 52/5 ------------------------checks and equation is true
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