Point: (3, 5)
Slope: 4
Equation: y = 4x-7
If you mean a slope of 6 and point of (-3, 5) then the equation is: y = 6x+23
It represents: y = x-35 or as x-y-35 = 0
35
It represents: y = x-35 or as x-y-35 = 0
35
Slope: -35 passing through (-5, -1) Equation: y = -35x-176
If you mean a slope of 6 and point of (-3, 5) then the equation is: y = 6x+23
It represents: y = x-35 or as x-y-35 = 0
35
It represents: y = x-35 or as x-y-35 = 0
35
It is: y--3 = -4(x--8) which works out as y = -4x-35
Points: (20, 18) and (35, 6) Slope: -4/5 Equation: y = -4/5x+34
slope intercept form is y = mx + b where m=slope and b=y-interceptfirst solve the equation for y7x-5y=357x=5y+355y=7x-35y=7x/5-35/5y=(7/5)x-7so the slope is 7/5 and the y-intercept is -7
hanks to the limitations of the browser through which questions are posted, it is not clear what the question is but, here goes: If the question was ea = 35, then the answer is a = ln(35) where ln are the natural logarithms.
69
To find the equation of a line in standard form (Ax + By = C) that passes through the point (-5, 1) with a slope of 7, we can use the point-slope form first: (y - 1 = 7(x + 5)). Simplifying this gives (y - 1 = 7x + 35) or (y = 7x + 36). Rearranging to standard form results in (-7x + y = 36) or (7x - y = -36). Thus, the standard form of the equation is (7x - y = -36).