It represents: y = x-35 or as x-y-35 = 0
It represents: y = x-35 or as x-y-35 = 0
The standard equation for a circle centered at the origin with a radius ( r ) is given by the formula ( x^2 + y^2 = r^2 ). In this equation, ( (x, y) ) represents any point on the circle, and ( r ) is the distance from the center to any point on the perimeter. This equation describes all points that are exactly ( r ) units away from the origin (0, 0).
If you mean a point of (0, 3) and a slope of 2 then the equation is y = 2x+3
To find the equation of a line in standard form (Ax + By = C) that passes through the point (-5, 1) with a slope of 7, we can use the point-slope form first: (y - 1 = 7(x + 5)). Simplifying this gives (y - 1 = 7x + 35) or (y = 7x + 36). Rearranging to standard form results in (-7x + y = 36) or (7x - y = -36). Thus, the standard form of the equation is (7x - y = -36).
To find the equation of a line with a slope of 2 that passes through the point (0, 3), you can use the slope-intercept form of a line, which is ( y = mx + b ). Here, ( m ) is the slope and ( b ) is the y-intercept. Since the point (0, 3) indicates that the y-intercept ( b ) is 3, the equation of the line is ( y = 2x + 3 ).
It represents: y = x-35 or as x-y-35 = 0
-40
If you mean a slope of 2 and a point of (1, 4) then the equation is y = 2x+2
It is: y-5 = 1(x-3) => y = x+2 or as x+2-y = 0
Y+2 = 2 (x-3)
General formula
2
The standard form is: 5x - y + 4 = 0
If you mean a point of (0, 3) and a slope of 2 then the equation is y = 2x+3
The equation of a vertical line passing through the point (a, b) is x a.
y = 1/3x+4/3
Points: (2, -3) and (-2, 0) Slope: -3/4 Equation: y = -0.75x-1.5