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Q: Which equation implies that A and B are independent events?
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If A and B are independent events than A and B' are independent?

Yes.


What is the difference between the multiplication rule for independent versus dependent events?

Given two events, A and B, Pr(A and B) = Pr(A)*Pr(B) if A and B are independent and Pr(A and B) = Pr(A | B)*Pr(B) if they are not.


How can the rule for the probability of 2 independent events be extended to 4 or 5 independent events?

p(A and B) = p(A) x p(B) for 2 independent events p(A and B and ...N) = p(A) x p(B) x p(C) x ...x p(N) In words, if these are all independent events, find the individual probabilities if each and multiply them all together.


If A and B are independent events then are A and B' independent?

if P(A)>0 then P(B'|A)=1-P(B|A) so P(A intersect B')=P(A)P(B'|A)=P(A)[1-P(B|A)] =P(A)[1-P(B)] =P(A)P(B') the definition of independent events is if P(A intersect B')=P(A)P(B') that is the proof


Suppose A and B are independent events. If p a 0.3 and what is?

.7


Definition of independent events?

when the occurance of an event B is not affected by the occurance of event A than we can say that these events are not dependent with each other


What does the equation for a linear relationship stand for?

y=mx+b is the equation for a linear relationship. y= the dependant variable m= the slope of the line x= the independent variable b= the y-intercept


How do you draw a Venn diagram to the probability of two independent events a and b?

the circles do not overlap at all.


Prove that the complement of A and B are independent events?

first prove *: if A intersect B is independent, then A intersect B' is independent. (this is on wiki answers) P(A' intersect B') = P(B')P(A'|B') by definition = P(B')[1-P(A|B')] since 1 = P(A) + P(A') = P(B')[1 - P(A)] from the first proof * = P(B')P(A') since 1 = P(A) + P(A') conclude with P(A' intersect B') = P(B')P(A') and is therefore independent by definition. ***note*** i am a student in my first semester of probability so this may be incorrect, but i used the first proof* so i figured i would proof this one to kinda "give back".


Which property is illustrated by the following statementIf AHAX= A RIG, then A RIG= A HAX?

Answer: The property that is illustrated is: Symmetric property. Step-by-step explanation: Reflexive property-- The reflexive property states that: a implies b Symmetric Property-- it states that: if a implies b . then b implies a Transitive property-- if a implies b and b implies c then c implies a Distributive Property-- It states that: a(b+c)=ab+ac If HAX implies RIG then RIG implies HAX is a symmetric property.


How do you find the probability of independent and dependent events?

P(A given B)*P(B)=P(A and B), where event A is dependent on event B. Finding the probability of an independent event really depends on the situation (dart throwing, coin flipping, even Schrodinger's cat...).


Event A has probability 0.4 event B has probability 0.5 If A and B are disjoint then the probability that both events occur is?

If two events are disjoint, they cannot occur at the same time. For example, if you flip a coin, you cannot get heads AND tails. Since A and B are disjoint, P(A and B) = 0 If A and B were independent, then P(A and B) = 0.4*0.5=0.2. For example, the chances you throw a dice and it lands on 1 AND the chances you flip a coin and it land on heads. These events are independent...the outcome of one event does not affect the outcome of the other.