There was no word problem, so it would be a null equation.
Solve it as you would normally. I could help if I had the equation. :) Fractions don't really change much; they just make the problem look more difficult.
The classical problem of angle trisection cannot be solved. If it were possible, it would provide the solution to a cubic equation. (-but it isn't and it won't!)
The letter X in the equation 14 plus X21 would be 2.5. this is a math problem.
Simplifying an equation often helps solve it.
if you solve by plugging in the known values ahead of time you won't have a general formula for the variable in the literal equation. Therefor if the known values change, you would have to start all over again, making each problem more individualized. Once the literal equation is solved for some variable, if the known values change all you have to do is plug in those new numbers to your literal equation, and out pops your answer
I would gingerly perform the step, write the solution,and go on to the next problem.
Solve it as you would normally. I could help if I had the equation. :) Fractions don't really change much; they just make the problem look more difficult.
Here is an example problem for you to consider: How many octaves are there between 13 Hz and 4 Hz? You would solve thisproblem using the following equation:
The classical problem of angle trisection cannot be solved. If it were possible, it would provide the solution to a cubic equation. (-but it isn't and it won't!)
That equation is impossible to solve because Sin-1(3) is an impossible proportion in a triangle. Earlier in the problem you might have made a mistake. Or, if that is the whole problem you cannot deduce an answer because there is no value of X, Real or imaginary that works in that equation.
The letter X in the equation 14 plus X21 would be 2.5. this is a math problem.
Simplifying an equation often helps solve it.
if you solve by plugging in the known values ahead of time you won't have a general formula for the variable in the literal equation. Therefor if the known values change, you would have to start all over again, making each problem more individualized. Once the literal equation is solved for some variable, if the known values change all you have to do is plug in those new numbers to your literal equation, and out pops your answer
if you want to "solve" this equation, you need an equals sign somehwere! For example, if the problem was 2x - 52=5 then you could solve. You add 52 (or 25) to both sides so the equation becomes 2x = 30. Then you divide both sides by 2 to get x=15
To solve an inequality word problem, first, identify the variables and the relationships described in the problem. Translate the words into a mathematical inequality, using symbols to represent the relationships (e.g., <, >, ≤, ≥). Then, solve the inequality just as you would with an equation, applying algebraic operations while keeping the inequality in mind. Finally, interpret the solution in the context of the original problem to provide a meaningful answer.
check your answer
To solve the equation x^2 + 7x - 80, you would get x = 6.105 and x = -13.105, I believe.