0
What else can I help you with?
How do you solve a equation in standard form when it has a fraction in it?
Solve it as you would normally. I could help if I had the equation. :) Fractions don't really change much; they just make the problem look more difficult.
How Do you solve a cubic equation by trisecting an angle?
The classical problem of angle trisection cannot be solved. If it were possible, it would provide the solution to a cubic equation. (-but it isn't and it won't!)
14 plus x 21 solve for x?
The letter X in the equation 14 plus X21 would be 2.5. this is a math problem.
If you were to solve the following system by substitution what would be the best variable to solve for and from what equation?
To determine the best variable to solve for in a system of equations by substitution, look for the equation that allows you to isolate a variable easily. Typically, choose the equation where one variable has a coefficient of 1 or -1, or is already expressed in terms of the other variable. This makes substitution straightforward and minimizes complexity in calculations. Once identified, you can solve for that variable and substitute it into the other equation.
Why would you want to solve a literal equation for a variable when you could simply plug in known values and then solve the resulting linear equation?
if you solve by plugging in the known values ahead of time you won't have a general formula for the variable in the literal equation. Therefor if the known values change, you would have to start all over again, making each problem more individualized. Once the literal equation is solved for some variable, if the known values change all you have to do is plug in those new numbers to your literal equation, and out pops your answer
How would you solve a 1 step equation?
I would gingerly perform the step, write the solution,and go on to the next problem.
How do you solve a equation in standard form when it has a fraction in it?
Solve it as you would normally. I could help if I had the equation. :) Fractions don't really change much; they just make the problem look more difficult.
Formula for number of octaves between two frequencies?
Here is an example problem for you to consider: How many octaves are there between 13 Hz and 4 Hz? You would solve thisproblem using the following equation:
How Do you solve a cubic equation by trisecting an angle?
The classical problem of angle trisection cannot be solved. If it were possible, it would provide the solution to a cubic equation. (-but it isn't and it won't!)
How would you solve x plus 3 equals sinx for x?
That equation is impossible to solve because Sin-1(3) is an impossible proportion in a triangle. Earlier in the problem you might have made a mistake. Or, if that is the whole problem you cannot deduce an answer because there is no value of X, Real or imaginary that works in that equation.
14 plus x 21 solve for x?
The letter X in the equation 14 plus X21 would be 2.5. this is a math problem.
If you were to solve the following system by substitution what would be the best variable to solve for and from what equation?
To determine the best variable to solve for in a system of equations by substitution, look for the equation that allows you to isolate a variable easily. Typically, choose the equation where one variable has a coefficient of 1 or -1, or is already expressed in terms of the other variable. This makes substitution straightforward and minimizes complexity in calculations. Once identified, you can solve for that variable and substitute it into the other equation.
Why would you want to solve a literal equation for a variable when you could simply plug in known values and then solve the resulting linear equation?
if you solve by plugging in the known values ahead of time you won't have a general formula for the variable in the literal equation. Therefor if the known values change, you would have to start all over again, making each problem more individualized. Once the literal equation is solved for some variable, if the known values change all you have to do is plug in those new numbers to your literal equation, and out pops your answer
Why would you want to simplify an algebraic equation?
Simplifying an equation often helps solve it.
How would you solve 2x minus 5 squared?
if you want to "solve" this equation, you need an equals sign somehwere! For example, if the problem was 2x - 52=5 then you could solve. You add 52 (or 25) to both sides so the equation becomes 2x = 30. Then you divide both sides by 2 to get x=15
How do you solve a inequality word problem?
To solve an inequality word problem, first, identify the variables and the relationships described in the problem. Translate the words into a mathematical inequality, using symbols to represent the relationships (e.g., <, >, ≤, ≥). Then, solve the inequality just as you would with an equation, applying algebraic operations while keeping the inequality in mind. Finally, interpret the solution in the context of the original problem to provide a meaningful answer.
How would you solve the equation x over 125?
To solve the equation ( x = 125 ), you would isolate ( x ) by multiplying both sides of the equation by 125. This would give you ( x = 125 \times \text{(some value)} ). If there is a specific value to solve for, please provide that for a more detailed solution.
