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73
Distance = sqrt(x2 + y2)
The distance between two points on a coordinate plane is calculated using the distance formula: Distance = √((x2 - x1)^2 + (y2 - y1)^2) In this case, the coordinates of the two points are (7, 1) and (7, 3). Since the x-coordinates are the same, we only need to calculate the difference in the y-coordinates, which is (3 - 1) = 2. Plugging this into the distance formula gives us: Distance = √((0)^2 + (2)^2) = √4 = 2. Therefore, the distance between the two points is 2 units.
It gives you the interquartile range
Your answer is 15
Distance = (9-5)2+(-6-1)2 = 65 and the square root of this is the distance between the points which is about 8.062257748
The distance between two points is: square root of [(x1-x2)^2 plus (y1-y2)^2] An exact answer could have been given if the points were properly enumerated.
If you mean points of: (2, 5) and (-4, 8) Distance is the square root of (2--4)^2+(5-8)^2 = 6.708 rounded
73
square root of (5-9)^2+(1+6)^2
square root of (5-9)^2+(1+6)^2
Distance: square root of [(4-7)squared+(6--3)squared)] = 3 times sq rt of 10 which is about 9.487 rounded
the area of a rectangle with width x and length 6x is 6x^2 what does the coefficient 6 mean in terms of the problem
If you mean: (4, 6) and (7, -3) then it is:- Distance is the square root of (4-7)^2+(6--3)^2 = 9.487 rounded to 3 decimal places
square root of (5-9)^2+(1+6)^2
Distance = sqrt(x2 + y2)
Yes, wavelength can be measured between corresponding points on two adjacent waves, such as measuring the distance between two consecutive wave peaks or troughs. This measurement gives an indication of the distance the wave travels in one complete cycle.