The distance between the points 46 and 73 can be calculated using the expression |73 - 46|. This simplifies to |27|, which equals 27. Thus, the distance between the points is 27 units.
73
The distance between two points in a Cartesian coordinate system can be calculated using the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Here, ((x_1, y_1)) and ((x_2, y_2)) are the coordinates of the two points. This formula is derived from the Pythagorean theorem, where the distance represents the hypotenuse of a right triangle formed by the differences in the x and y coordinates.
To find the distance between the points 51 and 9-6, we first need to determine the coordinates. Assuming the first point is (51, 0) and the second point is (9, -6), we can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Substituting in the values, the expression becomes: [ d = \sqrt{(9 - 51)^2 + (-6 - 0)^2} ]
Distance = sqrt(x2 + y2)
Distance = (9-5)2+(-6-1)2 = 65 and the square root of this is the distance between the points which is about 8.062257748
The distance between two points is: square root of [(x1-x2)^2 plus (y1-y2)^2] An exact answer could have been given if the points were properly enumerated.
If you mean points of: (2, 5) and (-4, 8) Distance is the square root of (2--4)^2+(5-8)^2 = 6.708 rounded
73
square root of (5-9)^2+(1+6)^2
square root of (5-9)^2+(1+6)^2
Distance: square root of [(4-7)squared+(6--3)squared)] = 3 times sq rt of 10 which is about 9.487 rounded
the area of a rectangle with width x and length 6x is 6x^2 what does the coefficient 6 mean in terms of the problem
If you mean: (4, 6) and (7, -3) then it is:- Distance is the square root of (4-7)^2+(6--3)^2 = 9.487 rounded to 3 decimal places
square root of (5-9)^2+(1+6)^2
Distance = sqrt(x2 + y2)
Yes, wavelength can be measured between corresponding points on two adjacent waves, such as measuring the distance between two consecutive wave peaks or troughs. This measurement gives an indication of the distance the wave travels in one complete cycle.