It is: y = -1/2x-8
Slope of a line perpendicular to x-y=16
It would be perpendicular to a line with the equation Y = 1/8 X.
No, they are perpendicular.
For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )
-3
y=-2 is parallel to the x-axis and perpendicular to the y-axis.
Slope of a line perpendicular to x-y=16
It would be perpendicular to a line with the equation Y = 1/8 X.
No, they are perpendicular.
For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )
A line that is perpendicular to ( y = 4x ) will have a slope that is the negative reciprocal of 4. Therefore, the slope of the perpendicular line is ( -\frac{1}{4} ). Any line with this slope, such as ( y = -\frac{1}{4}x + b ) (where ( b ) is any y-intercept), will be perpendicular to the original line.
The slope of the perpendicular is -(1/2) .
-3
3x+y = 4 y = -3x+4 Perpendicular slope: 1/3
-3
A perpendicular line has the negative reciprocal of the slope. The perpendicular line has a slope of 1/2 y=1/2 + 3 The 3 or y-intercept can really be any number though.
If: y = 2/5x+10 then the perpendicular slope is -5/2x or -2.5x