Every integer of the form 3*(2n-1) where n is an integer.
This statement is false. A number can be divisible by 3 and still be even, such as the number 6, which is both divisible by 3 and an even number. Divisibility by 3 is determined by the sum of a number's digits, not by whether the number is odd or even. Therefore, being divisible by 3 does not imply that a number must be odd.
If the second number is divisible by 6 then neither first nor second number is odd.
No odd numbers are divisible by even numbers.
No, 26871 is an odd number. No odd number is divisible by 2.
Yes because odd numbers are those which aren't divisible by 2.
This statement is false. A number can be divisible by 3 and still be even, such as the number 6, which is both divisible by 3 and an even number. Divisibility by 3 is determined by the sum of a number's digits, not by whether the number is odd or even. Therefore, being divisible by 3 does not imply that a number must be odd.
3411 is an odd number and is not divisible by 2. but, it is divisible by 3. 3411/3 = 1137
no 6 is divisible by 3 and so is 24 and so on ! lol
If the second number is divisible by 6 then neither first nor second number is odd.
5, 7, a bunch of numbers that are odd are not divisible by 3. numbers that are divisible by three can have all their numbers added together and come out with a number that is divisible by 3.
No, 26871 is an odd number. No odd number is divisible by 2.
No odd numbers are divisible by even numbers.
741 is an odd number so is not divisible by 2 741/3 = 247 so yes divisible by 3
Yes because odd numbers are those which aren't divisible by 2.
NO. Odd numbers are not always divisible by 5. Examples: 3 , 7, 9, 11, 13, 17, ... are odd numbers and they are not divisible by 5.
No odd number can be evenly divisible by 6. Since 6 is divisible by 2, any number that is divisible by 6 will automatically be divisible by 2.
no, as it is an odd number. (3 as the last digit)