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In the straight line equation: y = mx+b 'm' is the slope and 'b' is the y intercept

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Q: Which part of the equation gives the slope of the line?
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What part of the equation gives the slope of the line?

As for example in the straight line equation of y = 3x+9 the slope is 3 and the y intercept is 9


In the slope- intersect equation of a line which part of the equation gives the y coordinate of the point where the line crosses the y axis?

As for example in the equation: y = 2x+5 the slope is 2 and the y intercept is 5


In the slope-intercept equation of a line which part of the equation gives the y-coordinate of the point where the line crosses the y-axis?

The slope intercept equation also called the y intercept equation. It isy=mx+b in which x and y are coordinates, m is the slope of the line, and b is the y-intercept. so b would be the y-coordinate that intersects the y-axis.


Which part of the slope-intercept equation represents the y-intercept?

In the straight line equation of y = 3x+5 the slope is 3 and the y intercept is 5


What is the y intercept in an equation?

It is part of the equation that intercepts the y axis For example the straight line equation: y = 2x+4 is in slope-intercept form and 4 is the y intercept and 2 is the slope.


What is (-4-3)y-2x 2 in slope intercept form?

It is part of the equation that intercepts the y axis For example the straight line equation: y = 2x+4 is in slope-intercept form and 4 is the y intercept and 2 is the slope.


What part of the general slope intercept equation represents the slope?

The general form of the slope-intercept equation is y = mx + b. In that equation, the slope is m and the y intercept is b.


What part of the general slope-intercept equation represents the slope?

The slope-intercept form of an equation is: y = mx + b In this case, "m" is the slope, and "b" is the y-intercept.


What is the equation of a line perpendicular to y equals negative three x plus four that passes through -1 6?

You solve this type of problem using the following steps. 1) Write your original equation in slope-intercept form, that is, solved for "y". (The line is already in that form in this case). You can read off the slope directly: in an equation of the form: y = mx + b m is the slope. 2) Calculate the slope of the perpendicular line. Since the product of the slopes of perpendicular lines is -1, you can divide -1 by the slope you got in part (1). 3) Use the generic equation y - y1 = m(x - x1), for a line that has a given slope "m" and passes through point (x1, y1). Replace the given coordinates (variables x1 and y1). Simplify the resulting equation, if required.


Is the y intercept a part of slope?

The equation for slope is a=mx+b. The y-intercept is labeled b


Give the equation of a line that is perpendicular to a line?

(I am going to assume you are higher or in grade 9 math) So use the y=mx + b Use the negative reciprocal of the "m"(slope) part. Do this by simply flipping the fraction. This slope will be perpendicular to the original formula.


Is it true that if the slope of the line is positive the line is positive?

No.Unless the slope is zero, every line will extend from minus infinity to plus infinity. So part of it will be negative and part positive.No.Unless the slope is zero, every line will extend from minus infinity to plus infinity. So part of it will be negative and part positive.No.Unless the slope is zero, every line will extend from minus infinity to plus infinity. So part of it will be negative and part positive.No.Unless the slope is zero, every line will extend from minus infinity to plus infinity. So part of it will be negative and part positive.