In the straight line equation: y = mx+b 'm' is the slope and 'b' is the y intercept
As for example in the straight line equation of y = 3x+9 the slope is 3 and the y intercept is 9
As for example in the equation: y = 2x+5 the slope is 2 and the y intercept is 5
To write an equation that is part one parallel and part two perpendicular to a given line, start by identifying the slope of the original line from its equation, typically in the form (y = mx + b), where (m) is the slope. For the parallel part, use the same slope (m) for the new equation, resulting in the form (y = mx + b_1), where (b_1) is a different y-intercept. For the perpendicular part, use the negative reciprocal of the original slope, (-\frac{1}{m}), leading to the equation (y = -\frac{1}{m}x + b_2), with (b_2) being another y-intercept.
The general form of the slope-intercept equation is y = mx + b. In that equation, the slope is m and the y intercept is b.
The slope-intercept form of an equation is: y = mx + b In this case, "m" is the slope, and "b" is the y-intercept.
As for example in the straight line equation of y = 3x+9 the slope is 3 and the y intercept is 9
As for example in the equation: y = 2x+5 the slope is 2 and the y intercept is 5
The slope intercept equation also called the y intercept equation. It isy=mx+b in which x and y are coordinates, m is the slope of the line, and b is the y-intercept. so b would be the y-coordinate that intersects the y-axis.
In the straight line equation of y = 3x+5 the slope is 3 and the y intercept is 5
It is part of the equation that intercepts the y axis For example the straight line equation: y = 2x+4 is in slope-intercept form and 4 is the y intercept and 2 is the slope.
To write an equation that is part one parallel and part two perpendicular to a given line, start by identifying the slope of the original line from its equation, typically in the form (y = mx + b), where (m) is the slope. For the parallel part, use the same slope (m) for the new equation, resulting in the form (y = mx + b_1), where (b_1) is a different y-intercept. For the perpendicular part, use the negative reciprocal of the original slope, (-\frac{1}{m}), leading to the equation (y = -\frac{1}{m}x + b_2), with (b_2) being another y-intercept.
It is part of the equation that intercepts the y axis For example the straight line equation: y = 2x+4 is in slope-intercept form and 4 is the y intercept and 2 is the slope.
The general form of the slope-intercept equation is y = mx + b. In that equation, the slope is m and the y intercept is b.
The slope-intercept form of an equation is: y = mx + b In this case, "m" is the slope, and "b" is the y-intercept.
You solve this type of problem using the following steps. 1) Write your original equation in slope-intercept form, that is, solved for "y". (The line is already in that form in this case). You can read off the slope directly: in an equation of the form: y = mx + b m is the slope. 2) Calculate the slope of the perpendicular line. Since the product of the slopes of perpendicular lines is -1, you can divide -1 by the slope you got in part (1). 3) Use the generic equation y - y1 = m(x - x1), for a line that has a given slope "m" and passes through point (x1, y1). Replace the given coordinates (variables x1 and y1). Simplify the resulting equation, if required.
The equation for slope is a=mx+b. The y-intercept is labeled b
(I am going to assume you are higher or in grade 9 math) So use the y=mx + b Use the negative reciprocal of the "m"(slope) part. Do this by simply flipping the fraction. This slope will be perpendicular to the original formula.