Q: Which point lies on the graph of f(x) (x 4) 2?

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graph G(x)=[x]-1

In a euclidean graph, the position of a point on the graph is denoted by its Coordinates (x,y).

1) You write the equation in slope-intercept form, if it isn't in that form already. 2) An easy way to graph it is to start with the y-intercept. For example, if the intercept is +5, you graph the point (0, 5). Then you add an additional point, according to the slope. For example, if the slope is 1/2, you go 2 units to the right, and one up, and graph a point there.

The break even point on a graph usually appears as the location where 2 lines meet. This is where profit starts to go down for example.

The point in a Cartesian coordinate system where the axes intersect. On a 2-D graph, for example, this is where x and y equal zero. also the point (0,0) on a graph

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graph G(x)=[x]-1

There are two common ways to graph circles: using a cartesian graph and using a polar graph. For a cartesian graph, there are two familiar axes x and y which are orthogonal to each other. The formula for a circle is "x^2 + y^2 = a constant". In a polar graph, there are no axes and all points are defined by their radius from the center point, and the angle of the direction the point lies from the center. In a polar coordinate system, a circle is simply "r = a constant".

On a 2-D graph, a pair of numbers are used to determine the position of the point on a graph.

A number of point lies on it...................(-2,-44), (-1,-19),(0,6), (1,31), (2, 56)...............

What is the area bounded by the graph of the function f(x)=1-e^-x over the interval [-1, 2]?

a. (2,6). you draw it on a graph (x,y) b. c. d. make the triangle, a. lies between b. and c.

In a euclidean graph, the position of a point on the graph is denoted by its Coordinates (x,y).

Assuming the line is 3x - 2y = 4, the point (1, -1/2) lies in it.

The graph is a circle, with a diameter of 4, centered at the point (2, 0) on the x-axis.

Yes.

Calculate the derivative of the function.Use the derivative to calculate the slope at the specified point.Calculate the y-coordinate for the point.Use the formula for a line that has a specified slope and passes through a specified point.

1) You write the equation in slope-intercept form, if it isn't in that form already. 2) An easy way to graph it is to start with the y-intercept. For example, if the intercept is +5, you graph the point (0, 5). Then you add an additional point, according to the slope. For example, if the slope is 1/2, you go 2 units to the right, and one up, and graph a point there.