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There is no equation in the question, only the expression y6x.
II and IV
Yes, it is possible for a line to pass through exactly two quadrants. For instance, a line that has a positive slope can pass through the first and third quadrants if it extends from the second quadrant to the fourth. Similarly, a line with a negative slope can pass through the second and fourth quadrants. In both cases, the line does not intersect the axes in such a way that it enters all four quadrants.
A curved line can pass through (not threw) all four quadrants. The maximim for a straight line is three.
Points lying on the line through the origin that bisects the 2nd and 4th quadrants have coordinates where the y-coordinate is negative and the x-coordinate is positive. This line has a slope of -1, represented by the equation ( y = -x ). As such, any point on this line will have equal magnitude for its x and y values, but with opposite signs, indicating that they lie in the 2nd and 4th quadrants.
If the equation ( y = ax ) describes the graph of a line and the value of ( a ) is positive, the line will have a positive slope. This means that as ( x ) increases, ( y ) will also increase, resulting in an upward-sloping line from the origin. The line will pass through the origin (0,0) and extend into the first and third quadrants of the Cartesian plane.
I,ii
II and IV
Quadrants I and III, numbered from I at upper right (+, +) left and moving clockwise. The line passes through the origin (0,0).
It will pass through the first (when x is positive) and third quadrants (when x is negative, y will also be negative).
Yes, it is possible for a line to pass through exactly two quadrants. For instance, a line that has a positive slope can pass through the first and third quadrants if it extends from the second quadrant to the fourth. Similarly, a line with a negative slope can pass through the second and fourth quadrants. In both cases, the line does not intersect the axes in such a way that it enters all four quadrants.
A curved line can pass through (not threw) all four quadrants. The maximim for a straight line is three.
They satisfy the equation x + y = 0
I would say from an educated guess that it is 0. A straight line could avoid all quadrants if it were placed on the origins of the x and y axis.
At what point does line represented by the equation 8x + 4y = -4 intersects the y-axis, and at what point in the negative direction of x-axis.
What is the equation of the vertical line passing through (-5,-2)
The equation of a vertical line passing through the point (a, b) is x a.
Yes, a line can be in two quadrants if it crosses the axes. For example, a line that extends from the first quadrant to the third quadrant will intersect both the x-axis and y-axis, thus occupying portions of both quadrants. Similarly, lines can exist in any combination of quadrants depending on their slope and position relative to the axes.