II and IV
1
X = -1 The graph of this equation is a vertical line, passing through the point [ x = -1 ] on the x-axis. It's parallel to the y-axis, and extends to infinity in both directions ... up, through Quadrant II, and down, through Quadrant III.
y=6x is in the third quadrant while x is negative and in the first quadrant while x is positive.
Either the answer is the point in the second quadrant, at a distance of one unit from each of the coordinate axes, or the question is incomplete.
it lies in the 2nd and 4th quadrants
I,ii
II and IV
1
X = -1 The graph of this equation is a vertical line, passing through the point [ x = -1 ] on the x-axis. It's parallel to the y-axis, and extends to infinity in both directions ... up, through Quadrant II, and down, through Quadrant III.
y=6x is in the third quadrant while x is negative and in the first quadrant while x is positive.
It will pass through the first (when x is positive) and third quadrants (when x is negative, y will also be negative).
It passes through Quadrants II and IV. It also passes through the origin ... the point where the 'x' and 'y' axes cross. At that point, it's in all four quadrants.
Either the answer is the point in the second quadrant, at a distance of one unit from each of the coordinate axes, or the question is incomplete.
Quadrants I and III, numbered from I at upper right (+, +) left and moving clockwise. The line passes through the origin (0,0).
Assuming sin equals 0.3237, the angle is in quadrant I.
depends on line slope