Becasue the browser used by this site is unable to display most mathematical notation, this may not be the correct recursive formula, but:if a(1) = 2 and
a(n) = 4*a(n-1)^2 then
then a(2) = 4*2^2 =4*4 =16
and a(3) = 4*4^2 = 4*16 = 64
0,1,1,2,3,5,8,13
2,1,0 is th sequence of its terms
The first four terms are 3 9 27 81 and 729 is the 6th term.
because you add the first 2 terms and the next tern was the the sum of the first 2 terms.
The sum of the terms in a sequence is called a series. Sequence is a function whose domain is the natural numbers. So f(1)= first entry in the sequence, and f(2) is the next.... f(n) is the nth term. We usually don't write sequences that way. Instead of f(1) we write, a1 to refer to the first term. The function tells us the rule we use to find the terms of the sequence. So for example, f says take n and square it. Then the first 3 terms of the sequence are 1, 4 and 9 and the first 3 terms of the series are 1, 5 and 14
Which sequence? Oh, that one! The first three terms are 1, 2 and 72.
0,1,1,2,3,5,8,13
2,1,0 is th sequence of its terms
4,8,12,16,20
the first 4 terms of the sequence which has the nth term is a sequence of numbers that that goe together eg. 8,12,16,20,24 the nth term would be 4n+4
5
it is 8.
field, record, table, database
123456
The sequence 4n + 7 represents a linear sequence where n is the position in the sequence. To find the first five terms, substitute n with 1, 2, 3, 4, and 5 respectively. Thus, the first five terms are 11, 15, 19, 23, and 27.
a1=2 d=3 an=a1+(n-1)d i.e. 2,5,8,11,14,17....
The first four terms are 3 9 27 81 and 729 is the 6th term.