I think the formula is something like work (energy) is mass by height by gravity. as gravity is a constant, dont worry about it in comparison.
25*10 is 250
50*5 is 250. They require the same effort
They are the same- weight x distance equals weight times distance.
F = M AM = F/A = 200/5 = 40 kg
volume of 1 cement bag is 0.035cu.m.
The volume is(1000)/(density of cement in kg/m3) cubic meters.
the size of you!>!CK
They are the same- weight x distance equals weight times distance.
Lifting a 50 kg sack a vertical distance of two meters requires more work because work is equal to force multiplied by distance. In this case, the force is greater (50 kg as opposed to 25 kg) even though the distance is shorter.
How many cubic meters in 1 cement bag of 50kgs
F = M AM = F/A = 200/5 = 40 kg
volume of 1 cement bag is 0.035cu.m.
The work done in lifting a 60kg crate a vertical distance of 10 meters is given by the formula: work = force x distance x cos(theta), where force = weight x gravitational acceleration = 60kg x 9.8 m/s^2, distance = 10m, theta is the angle between the force and direction of displacement (which is 0 in this case, as it's lifting vertically). Plugging in the values, the work done is approximately 5,880 Joules.
The volume is(1000)/(density of cement in kg/m3) cubic meters.
The number of bags of cement needed for 10 square meters of ceramic floor tiles depends on the thickness of the mortar bed and the type of tile. Typically, a standard tile installation requires about 3-4 kg of cement per square meter. Therefore, for 10 square meters, you would need approximately 30-40 kg of cement, which translates to about 1-2 bags, depending on the size of the bags (usually 25 kg or 50 kg). Always check specific installation guidelines for the exact requirements.
Calculate the area (for a rectangle, that would be length x width), then divide by the number of square meters covered by each bag.
The answer depends on whether the ball is thrown vertically upwards or downwards. That critical piece of information is not provided!
Here are two physics problems involving work and gravitational potential energy: Problem 1: A 5 kg box is lifted 2 meters vertically against gravity. Calculate the work done in lifting the box and the change in gravitational potential energy. Problem 2: A 10 kg object is pushed horizontally across a frictionless surface for a distance of 5 meters. Calculate the work done in pushing the object and the change in gravitational potential energy if the object is then lifted 3 meters vertically.
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