There is no way to answer this question without more information on the equation and other options. That are no statements to choose from for the two lines Y 6 and X 3.
No, not always. It depends on if the original biconditional statement is true. For example take the following biconditional statement:x = 3 if and only if x2 = 9.From this biconditional statement we can extract two conditional statements (hence why it is called a bicondional statement):The Conditional Statement: If x = 3 then x2 = 9.This statement is true. However, the second statement we can extract is called the converse.The Converse: If x2=9 then x = 3.This statement is false, because x could also equal -3. Since this is false, it makes the entire original biconditional statement false.All it takes to prove that a statement is false is one counterexample.
A true statement.
You must reverse the sense of inequality because, in essence, you're taking the opposite of both sides. In order to more properly show this, here's an example. 3>2 Three is greater than two. True statement, right? Let's multiply both sides by -1 -3>-2 The statement is no longer true. In order to keep the equation true, you must flip the inequality. As in -3<-2 Now, the statement is true again.
-3/7 < -1/7
No, that is not true.
TRUE:: The first two lines lie in the same plain, but are perpendicular to each other. The third line passes through the plane of the first two lines so it is also perpendicular. Think 3-dimension. !!!!!
true
No, not always. It depends on if the original biconditional statement is true. For example take the following biconditional statement:x = 3 if and only if x2 = 9.From this biconditional statement we can extract two conditional statements (hence why it is called a bicondional statement):The Conditional Statement: If x = 3 then x2 = 9.This statement is true. However, the second statement we can extract is called the converse.The Converse: If x2=9 then x = 3.This statement is false, because x could also equal -3. Since this is false, it makes the entire original biconditional statement false.All it takes to prove that a statement is false is one counterexample.
3
about two-three lines
That is false. This type of statement is only true for prime numbers, not for compound numbers such as 6. Counterexample: 2 x 3 = 6
A true statement.
3.18 > 3 1/8
Sometimes true. (when the numbers are mutually prime) e.g. it's true for 5 and 7, 8 and 3. But it's not true when they have a factor in common e.g. 6 and 8, or 15 and 20.
You must reverse the sense of inequality because, in essence, you're taking the opposite of both sides. In order to more properly show this, here's an example. 3>2 Three is greater than two. True statement, right? Let's multiply both sides by -1 -3>-2 The statement is no longer true. In order to keep the equation true, you must flip the inequality. As in -3<-2 Now, the statement is true again.
How can the following definition be written correctly as a biconditional statement? An odd integer is an integer that is not divisible by two. (A+ answer) An integer is odd if and only if it is not divisible by two
An if-then statement, or simply an if statement, checks if a stated condition is true. If the condition is true, then a block of code will then execute. Example: if number equals 3 print out "Number equals 3" An if-then-else statement, or simply an if-else statement, checks if a stated condition is true. If the condition is true, then a certain block of code will then execute. If the condition is false, then a different block of code will then execute. Example: if number equals 3 print out "Number equals 3" else print out "Number does not equal 3" For both if statements and if-else statements, there is only one stated condition. The difference between them is that an if statement will only cause something to happen if the condition is true. An if-else statement will execute a block of code whether the condition is true or false.