64 + 66 + 68 = 198
65, 66, 67
Let the first even number be x. Then the second even number would be x + 2, and the third even number would be x + 4. The sum of these numbers is x + (x + 2) + (x + 4) = 3x + 6. We set this equal to 204 and solve for x: 3x + 6 = 204 --> 3x = 198 --> x = 66. Therefore, the three consecutive even numbers are 66, 68, and 70.
200, 500 and 201.
There is only one number that equals 198. The number is . . . . . . . . . . 198 .
64 + 66 + 68 = 198
198, 199 and 200 if you add them.
The numbers are 65, 66, and 67..
The numbers are 195, 196, 197 and 198.
65, 66, 67
201
The LCM of the given three numbers is 198
Let the first even number be x. Then the second even number would be x + 2, and the third even number would be x + 4. The sum of these numbers is x + (x + 2) + (x + 4) = 3x + 6. We set this equal to 204 and solve for x: 3x + 6 = 204 --> 3x = 198 --> x = 66. Therefore, the three consecutive even numbers are 66, 68, and 70.
200, 500 and 201.
48, 49, 50, 51
There is only one number that equals 198. The number is . . . . . . . . . . 198 .
It is: 2*3*3*11 = 198