The numbers are 65, 66, and 67..
48, 49, 50, 51
There is no set of three consecutive integers whose sum is 71.
The sum of three consecutive integers is -72
There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.
That isn't possible. The three consecutive number are assumed to be integers; the sum of three consecutive integers is always a multiple of 3 (try it out).
65, 66, 67
201
There is no set of three consecutive integers for 187.
Three consecutive integers have a sum of 12. What is the greatest of these integers?
48, 49, 50, 51
There is no set of three consecutive integers for 106.
There is no set of three consecutive integers whose sum is 71.
The sum of three consecutive integers is -72
9240 is the product of the three consecutive integers 20, 21, and 22.
The sum of the squares of the three consecutive integers 11, 13, 15 = 515
They are: 65+66+67 = 198
There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.