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What is the graph of 3x plus 2y equals 13?
3x + 2y = 13Subtract 3x from each side:2y = -3x + 13Divide each side by 2:y = (-3/2)x + (13/2)The graph is a straight line, with a slope of (-3/2),through the point (0, 13/2) .
How do you graph a line parallel to y3x 2 with a y-intercept of -3?
If you mean: y = 3x+2 then the parallel line will be y = 3x-3
The graph of 3x plus 4y-4 equals 0 crosses the line y equals -2 at what value of x?
3x + 4y - 4 = 0 y = -2 3x + 4(-2) - 4 = 0 3x - 8 - 4 = 0 3x = 12 x = 4 (4,-2)
How do you graph fx-x-1 3 gx-x-2 and hx -3x-1?
graph G(x)=[x]-1
How would you graph y equals -3x plus 6?
This is one way to do it 1) Find the x and y -intercepts y = -3x + 6 Plug in 0 for "x" and solve for "y" y = -3(0) + 6 y = 6 That means that when x = 0, y = 6 So plot the first point (0, 6) onto the graph <-- this is your x-intercept by the way Next do the opposite by plugging in 0 for "y" and solve for "x" y = -3x + 6 0 = -3x + 6 3x = 6 x = 2 That means that when y = 0, x = 2 Plot the point (0,2) on the graph. This is your y-intercept. Now, you can just connect the two points and you will get your line.
