Let P be perimeter, A is area, L is length, and W is width.A = L x W, P = 2L + 2W; you know P and W, so L = (P - 2W)/2and A = W x (P - 2W)/2
L = P/2 - W.
If length = L and width = W then area A = L*W and perimeter P = 2(L+W). So, from the area equation, L = A/W Substituting this in the equation for P gives P=2(A/W + W) = 2A/W + 2W Then multiplying through by W gives PW = 2A + 2W2 or, in standrad form, 2W2 - PW + 2A = 0 Then W = 1/4*[P +/- sqrt(P2 - 16A)] The two solutions of this quadratic will be W and L.
Perimeter = 2*L + 2*W Area = L*W L = Area / W Perimeter = 2*Area / W + 2*W W * Perimeter = 2*Area + 2*W^2 Let A=area, and P= perimeter. 0=2W^2-PW+2A Quadratic formula: W= (P + root(P^2-16A))/4 or W= (P - root(P^2-16A))/4 Once you have W, L is simply A/W. Have fun, and maybe include some numbers to work with next time.
If we're talking Width, Length and Perimeter then W = P/2 - L
George W. P. Hunt was born on 1859-11-01.
George W. P. Hunt died on 1934-12-24.
George W. Norris
George W. Norris
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George W. P Rengstorff has written: 'Friction and wear of iron in sulfuric acid' -- subject(s): Tribology, Fatigue, Iron
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noo he did not C; im srry for ur time >,<
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