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How do you find the area from the perimeter and width of a rectangle?
Let P be perimeter, A is area, L is length, and W is width.A = L x W, P = 2L + 2W; you know P and W, so L = (P - 2W)/2and A = W x (P - 2W)/2
What is W equals P half minus L solve for L?
L = P/2 - W.
How do you determine length and width if given the area and perimeter?
If length = L and width = W then area A = L*W and perimeter P = 2(L+W). So, from the area equation, L = A/W Substituting this in the equation for P gives P=2(A/W + W) = 2A/W + 2W Then multiplying through by W gives PW = 2A + 2W2 or, in standrad form, 2W2 - PW + 2A = 0 Then W = 1/4*[P +/- sqrt(P2 - 16A)] The two solutions of this quadratic will be W and L.
How do you find the length and wide of an area if you know the perimeter and an area?
Perimeter = 2*L + 2*W Area = L*W L = Area / W Perimeter = 2*Area / W + 2*W W * Perimeter = 2*Area + 2*W^2 Let A=area, and P= perimeter. 0=2W^2-PW+2A Quadratic formula: W= (P + root(P^2-16A))/4 or W= (P - root(P^2-16A))/4 Once you have W, L is simply A/W. Have fun, and maybe include some numbers to work with next time.
Which equation solves for w in terms of L and P?
If we're talking Width, Length and Perimeter then W = P/2 - L
