If we're talking Width, Length and Perimeter then W = P/2 - L
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If the equation is 6 = -10 - p/5 then multiply all terms by 5 :-30 = -50 - p : p = -50 - 30 = -80
l = 100/p inches.
If length = L and width = W then area A = L*W and perimeter P = 2(L+W). So, from the area equation, L = A/W Substituting this in the equation for P gives P=2(A/W + W) = 2A/W + 2W Then multiplying through by W gives PW = 2A + 2W2 or, in standrad form, 2W2 - PW + 2A = 0 Then W = 1/4*[P +/- sqrt(P2 - 16A)] The two solutions of this quadratic will be W and L.
There can be no solution because there is no equation (or inequality) but only an expression.
The perimeter is equal to the length of each side added together, and a rectangle has four sides, so the equation could be written as s1+s2+s3+s4=P. However, because opposite sides of a rectangle are equal in length, we can call s1 and s2 "L" and s3 and s4 "W" and rewrite the equation as L+L+W+W=P, which simplifies to 2L+2W=p, or finally 2(L+W)=P.