I know something is missing here but if x=5 then 5-1=4 (a real number)
Please try again and make it more clear.
Here are a few: 0 = 1 x = x + 1 (subtract "x" on each side, and you get the previous one!) x2 = -1 (if you want real numbers; however, it has two solutions in the complex numbers) ln x = -1 (same as above: no solution in the real numbers, but it has a solution in the complex numbers) ln x = 0 (no solution, neither in the real numbers, nor in the complex numbers) 0x = 5
f(x)=(x/|x-3|)+1; domain is all real numbers except 3. f(x)=(x/(|x-3|+1)); domain is all real numbers.
Given a function f(x), the domain is all of the numbers you are allowed to put in it (in other words x), and the range is all of the numbers you can get from it (in other words f(x)).Here are a few examples:f(x) = 3x+2D: All real numbers (-inf,inf)R: All real numbers (-inf,inf)f(x) = |x| + 2 (where |x| is the absolute value of x)D: All real numbers (-inf,inf)R: All real numbers greater than or equal to 2 [2,inf)f(x) = 1/(4x^2-1)D: All real numbers except 1/2 and -1/2 (because if you plug in either of those you get 1/0 which is undefined) (-inf,-1/2) u (-1/2,1/2) u (1/2,inf)R: All real numbers greater than or equal to -1 except 0. [-1,0) u (0,inf)
x = x + 1x squared = -1 (if you only accept real numbers - this equation does have solutions in the complex numbers)sin x = 2 (the sine can only be in the range -1 to +1)
There is no inequality in the question!
I know something is missing here but if x=5 then 5-1=4 (a real number) Please try again and make it more clear.
All real numbers, except 0, have a multiplicative inverse. For any real x, (x not = 0), there exists a real number y such that x*y = 1. This y is denoted by 1/x.
Here are a few: 0 = 1 x = x + 1 (subtract "x" on each side, and you get the previous one!) x2 = -1 (if you want real numbers; however, it has two solutions in the complex numbers) ln x = -1 (same as above: no solution in the real numbers, but it has a solution in the complex numbers) ln x = 0 (no solution, neither in the real numbers, nor in the complex numbers) 0x = 5
f(x)=(x/|x-3|)+1; domain is all real numbers except 3. f(x)=(x/(|x-3|+1)); domain is all real numbers.
Among the real whole numbers, you only have two choices: -1 x 11 and 1 x -11
One 0 and 1 0 X 0 = 0 1 X 1 = 1Only positive 1 though.Negative 1 will produce the answer of a positive 1.Solve x = x^2x^2 - x = 0x ( x - 1 ) = 0Has solutions x=0 and x=1
Given a function f(x), the domain is all of the numbers you are allowed to put in it (in other words x), and the range is all of the numbers you can get from it (in other words f(x)).Here are a few examples:f(x) = 3x+2D: All real numbers (-inf,inf)R: All real numbers (-inf,inf)f(x) = |x| + 2 (where |x| is the absolute value of x)D: All real numbers (-inf,inf)R: All real numbers greater than or equal to 2 [2,inf)f(x) = 1/(4x^2-1)D: All real numbers except 1/2 and -1/2 (because if you plug in either of those you get 1/0 which is undefined) (-inf,-1/2) u (-1/2,1/2) u (1/2,inf)R: All real numbers greater than or equal to -1 except 0. [-1,0) u (0,inf)
x2 + 1 can't be factored in the real numbers. If complex numbers are acceptable, it can be factored as (x + i)(x - i).
x = x + 1x squared = -1 (if you only accept real numbers - this equation does have solutions in the complex numbers)sin x = 2 (the sine can only be in the range -1 to +1)
Let x and y be the dimensions of the rectangle. Therefore, x+y=107 and x*y=2310. The question is the find two real numbers such that they satisfy the above statement. There are x=77 and y=32 that satisfy the statement above
all real numbers except 1
There is no inequality in the question!