Sometimes, given a random variable X, you want to know the value, X= x such that the proportion of values that which are at least as extreme as x is a given percentage.
When testing for the location of the mean, m, of a normal distribution you may wish to be 95% sure that the mean lies within some interval. If the interval is symmetric about m, and Z(m) is the z score for the mean, then you require Prob(Z(l) < Z(m) < Z(u)) = 0.05. This establishes the lower and upper bounds for the interval. It is easier to convert these to the raw scores to determine the lower and upper bounds for x-bar for testing whether or not the sample mean is consistent with the hypothesised mean.
Yes.z = (raw score - mean)/standard error.Since the standard error is positive, z < 0 => (raw score - mean) < 0 => raw score < mean.
z score = (test score - mean score)/SD z score = (87-81.1)/11.06z score = 5.9/11.06z score = .533You can use a z-score chart to calculate the probability from there.
There is not enough information to answer your question. To determine a Z-Score, the mean and standard deviation is also required.
A z-score requires the mean and standard deviation (or standard error). There is, therefore, not enough information to answer the question.
Go back to the basic data, estimate the sample mean and the standard error and use these to estimate the Z-score.
Without more information you cannot.
z = (x - μ) / σ is the formula where x is the raw score and z is the z-score. μ and σ are the mean and standard deviations and must be known numbers. Multiply both sides by σ zσ = x-μ Add μ to both sides μ + zσ = x x = μ + zσ You calculate the raw score x , given the z-score, μ and σ by using the above formula.
If the Z Score of a test is equal to zero then the raw score of the test is equal to the mean. Z Score = (Raw Score - Mean Score) / Standard Deviation
Yes.z = (raw score - mean)/standard error.Since the standard error is positive, z < 0 => (raw score - mean) < 0 => raw score < mean.
No.
z score = (test score - mean score)/SD z score = (87-81.1)/11.06z score = 5.9/11.06z score = .533You can use a z-score chart to calculate the probability from there.
There is not enough information to answer your question. To determine a Z-Score, the mean and standard deviation are also required.
Let your raw score be x and M the mean and S the standard deviation. The Z score for your specific x is Z=(x-M)/S So say your score is 80 (out of 100) and the mean is 70 and the standard deviation is 10. Then the z score for your 80 is: (80-70)/10=1 If on the other hand you got a 60, then the z score would be -1.
There is not enough information to answer your question. To determine a Z-Score, the mean and standard deviation is also required.
A z-score requires the mean and standard deviation (or standard error). There is, therefore, not enough information to answer the question.
There is insufficient information in the question to answer it. To determine Z score, you need raw score, mean, and standard deviation. Please restate the question.
This question cannot be answered. You need the mean and standard deviation in order to compute a Z score for a Raw score. Please restate the question.