Even numbers are the multiples of 2 and are those numbers which end with one of {0, 2, 4, 6, 8}; odd numbers are those which are not multiples of two and are those numbers which end with {1, 3, 5, 7, 9}.
When an even number is multiplied by an even or odd number the result is always an even number.
4 is an even number; thus all its multiples are even numbers.
Any number that ends with a 3 is an odd number.
There are no numbers which are both odd and even; therefore no multiple of 4 can end in a 3.
A number that ends in 3 is an odd number, as it is not divisible by 2. For a number to be a multiple of 6, it must be divisible by both 2 and 3. Since a number ending in 3 is not divisible by 2, it cannot be a multiple of 6. In other words, any number ending in 3 will always have a remainder when divided by 6.
A number ending in 0 or 5, whose digits sum to a multiple of 3.
A prime number has no factors other than 1 and itself. Each multiple of fifteen includes 3, 5, and 15 among its factors.
No, 92 is not a multiple of 3. A quick way to check if a number is a multiple of 3 is: add up the digits of the number you are checking; if this sum equals 3 or a multiple of 3, then the number is a multiple of 3. So in this case, 92 --> 9+2=11, which is not a multiple of 3. If you have to you can add again, so for 11 --> 1+1=2, which is not a multiple of 3. You can always repetitively add until you get to a single digit answer: if it's 3,6 or 9 then it's a multiple of 3. Also if your sum is 9 or a multiple of 9, then the original number is a multiple of 9. To check for 6, if a number is a multiple of 3, and also a multiple of 2 (an even number), then the number is a multiple of 6.
No. To find if a number is a factor of 3, add the number's digits. If the resulting number is a multiple of 3, then the original number is a multiple of 3. In 4339, the digits of the number added together is 19, which is not a multiple of 3.
Because the multiples of 4 are even numbers and 3 is an odd number
A number that ends in 3 is an odd number, as it is not divisible by 2. For a number to be a multiple of 6, it must be divisible by both 2 and 3. Since a number ending in 3 is not divisible by 2, it cannot be a multiple of 6. In other words, any number ending in 3 will always have a remainder when divided by 6.
A number ending in 0 or 5, whose digits sum to a multiple of 3.
4 is an even number and so all multiples of 4 must be even. A number ending in 3 is not even and so cannot be a multiple of 4.
A prime number has no factors other than 1 and itself. Each multiple of fifteen includes 3, 5, and 15 among its factors.
Any multiple of four must be even; any number ending in three is odd. Look at the multiples of four from 1 to 9. They are in the order : 4,8,12,16,20,24,28,32,36. Now, any number when multiplied by 4, will have the one's digit as the one's digit of the above multiples In the above multiples, no multiple has 3 as the one's digit, i.e., no multiple ends in three. Take an example. 15x4 will have 0 in the one's digit because 5x4 = 20 and has 0 in the one's place.
It would help to have that other number. If the other number is a multiple of 3, the LCM is that number. If it is not a multiple of 3, the LCM is 3 times that number.
No, 92 is not a multiple of 3. A quick way to check if a number is a multiple of 3 is: add up the digits of the number you are checking; if this sum equals 3 or a multiple of 3, then the number is a multiple of 3. So in this case, 92 --> 9+2=11, which is not a multiple of 3. If you have to you can add again, so for 11 --> 1+1=2, which is not a multiple of 3. You can always repetitively add until you get to a single digit answer: if it's 3,6 or 9 then it's a multiple of 3. Also if your sum is 9 or a multiple of 9, then the original number is a multiple of 9. To check for 6, if a number is a multiple of 3, and also a multiple of 2 (an even number), then the number is a multiple of 6.
No. To find if a number is a factor of 3, add the number's digits. If the resulting number is a multiple of 3, then the original number is a multiple of 3. In 4339, the digits of the number added together is 19, which is not a multiple of 3.
Uhhh.. you cant
you add up the digits, and if the sum is a multiple of 3, then the number is divisible by 3!
3 is the smallest number that is a factor 66 and a multiple of 3