In two dimensions (to keep it simple), the magnitude is the square root of (x2 + y2). This follows directly from Pythagoras' Law. Now, experiment a bit with this formula, inserting some numbers, to get a feel for how the magnitude depends on the components.
Pythagoras' Law can be extended to 3 or more dimensions in an analogous fashion.
no a vector cannot have a component greater than the magnitude of vector
No.
No a vector may not have a component greater than its magnitude. When dealing with highschool phyics problems, the magnitude is usually the sum of two or more components and one component will offset the other, causing the magnitude to be less then its component
No, because the components along any other direction is v*cos(A) where v is the magnitude of the original vector and A is the angle between the direction of the original vector and the direction of the component. Since the absolute value of cos(A) cannot be greater than 1, then v*cos(A) cannot be greater than v.
No, by definiton, a unit vector is a vector with a magnitude equal to unity.
no a vector cannot have a component greater than the magnitude of vector
A vector component can never be greater than the vector's magnitude. The magnitude of a vector is the length of the vector and is always greater than or equal to any of its individual components.
No, a vector's component cannot be greater than the vector's magnitude. The magnitude represents the maximum possible magnitude of a component in any direction.
No, a vector component is a projection of the vector onto a specific direction. It cannot have a magnitude greater than the magnitude of the vector itself.
No, a component of a vector cannot be greater than the magnitude of the vector itself. The magnitude of a vector is the maximum possible value that can be obtained from its components.
No.
No.
No.
No.
No a vector may not have a component greater than its magnitude. When dealing with highschool phyics problems, the magnitude is usually the sum of two or more components and one component will offset the other, causing the magnitude to be less then its component
No, because the components along any other direction is v*cos(A) where v is the magnitude of the original vector and A is the angle between the direction of the original vector and the direction of the component. Since the absolute value of cos(A) cannot be greater than 1, then v*cos(A) cannot be greater than v.
No, a vector cannot have zero magnitude if one of its components is not zero. The magnitude of a vector is determined by the combination of all its components, so if any component is not zero, the vector will have a non-zero magnitude.