So that you can plot out the points of a straight line on graph paper.
yes because you will need the slope and y-intercept to find the equation of a line and the point through which the line passes is the y-intercept so it is yes!!!!!!! Good Luck!!!!!!!!!!!!!
An equation of a line requires two parameters. The slope, by itself, is not enough.
To determine the intercepts of a line, you need to find where the line crosses the x-axis and y-axis. The x-intercept occurs when y = 0, and the y-intercept occurs when x = 0. If you have the equation of the line, you can substitute these values to find the respective intercepts. Please provide the equation of the line for specific intercept values.
To find the equation of a line, you typically need a point and a slope. If the line is represented in the form (y = mx + b), where (m) is the slope and (b) is the y-intercept, you can substitute the values accordingly. If you provide specific points or characteristics of the line, I can help you derive the exact equation. Please clarify the details related to "2-1."
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In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
yes because you will need the slope and y-intercept to find the equation of a line and the point through which the line passes is the y-intercept so it is yes!!!!!!! Good Luck!!!!!!!!!!!!!
An equation of a line requires two parameters. The slope, by itself, is not enough.
To determine the intercepts of a line, you need to find where the line crosses the x-axis and y-axis. The x-intercept occurs when y = 0, and the y-intercept occurs when x = 0. If you have the equation of the line, you can substitute these values to find the respective intercepts. Please provide the equation of the line for specific intercept values.
To find the equation of a line, you typically need a point and a slope. If the line is represented in the form (y = mx + b), where (m) is the slope and (b) is the y-intercept, you can substitute the values accordingly. If you provide specific points or characteristics of the line, I can help you derive the exact equation. Please clarify the details related to "2-1."
The equation of line can be easily made if the slope and y-intercept are known, in the form of y equals mx plus b, where m is the slope and b is the y-intercept. The quadratic equation may need to be utilized if the previous equation cannot be used.
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By finding the line of best fit and using the straight line equation formula.
Certainly you will need a graph paper of exact answer if u mean 4,3 on x-axis and 6,11 on y-axis.The formula is y=mc.It is called "Equation of straight line".
There are three variables in the equation. In order to find numbers for all of them,you need three separate independent equations.As it is now, the graph of that equation is a line in 3-dimensional space, andevery point on the line is a 'solution' to the equation. We don't have to tell youhow many points there are on a line, do we ?
Subtract the equation of one line from the equation of the other
If the x intercept is a and the y intercept is b, then the equation of the line is bx + ay = ab