The equation of line can be easily made if the slope and y-intercept are known, in the form of y equals mx plus b, where m is the slope and b is the y-intercept. The quadratic equation may need to be utilized if the previous equation cannot be used.
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
An equation of a line requires two parameters. The slope, by itself, is not enough.
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By finding the line of best fit and using the straight line equation formula.
Subtract the equation of one line from the equation of the other
If the x intercept is a and the y intercept is b, then the equation of the line is bx + ay = ab
As for example in the straight line equation of y=3x+5 the slope is 3 and the y intercept is 5
By substitution
The question is suppose to read: Find the equation of the line tangent to y=(x²+3x)²(2x-2)³, when x=8
Substitute the coordinates of the point into the equation of the line. If the result is true, then the point is on the line.
So that you can plot out the points of a straight line on graph paper.
yes because you will need the slope and y-intercept to find the equation of a line and the point through which the line passes is the y-intercept so it is yes!!!!!!! Good Luck!!!!!!!!!!!!!