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Why does a brick and a feather fall at the same rate on the moon?
Wiki User
∙ 9y ago
The free-fall of objects (falling objects in vacuum or outside the atmosphere) is solely dependent on gravitational pull (in this case the gravitational pull of the moon) and is not influenced by factors such as weight, density or surface area since there is no atmosphere to resist such factors. Therefore a brick and a feather would fall at the same rate on the moon.
F = GmM / R^2 force of grav
But
A = F / m acceleration due to grav
So,
F / m = GM / R^2 = A
So the acceleration due to grav is GM / R^2
Notice small m is not an important consideration for acceleration in the formula for acceleration due to gravity... we define small m the mass of the smaller object (feather or brick) and big M the mass of the bigger one (moon).
Another way to say this: acceleration with the same force is inversely proportional to mass A= f/m , but the force due to grav is proportional to mass. GMm/R^2. This leads to the cancellation of small m.
Wiki User
∙ 9y ago
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